python - 基于共同头部或尾部的连接列表

Question

解决以下问题的最快方法是什么我将根据常见的头部或尾部加入几个列表

input = ([5,6,7], [1,2,3], [3,4,5], [8, 9])
output = [1, 2, 3, 4, 5, 6, 7]

Answer 1

>>> def chain(inp):
    d = {}
    for i in inp:
        d[i[0]] = i[:], i[-1]
    l, n = d.pop(min(d))
    while True:
        lt, n = d.pop(n, [None, None])
        if n is None:
            if len(d) == len(inp) - 1:
                l, n = d.pop(min(d))
                continue
            break
        l += lt[1:]
    return l

>>> chain(input)
[1, 2, 3, 4, 5, 6, 7]
>>> chain(([5,6,7], [1,2,10], [3,4,5], [8, 9]))
[3, 4, 5, 6, 7]