135

如果我有城镇或地区的经纬度坐标，如何在 Google 地图中获取城市名称？

我尝试使用纬度，经度，我得到了国家，但我不知道如何得到城市名称。

4

15 回答 15

247

从一个Geocoder对象，你可以调用getFromLocation(double, double, int)方法。它将返回Address具有方法的对象列表getLocality()。

Geocoder gcd = new Geocoder(context, Locale.getDefault());
List<Address> addresses = gcd.getFromLocation(lat, lng, 1);
if (addresses.size() > 0) {
    System.out.println(addresses.get(0).getLocality());
}
else {
   // do your stuff
}
于 2010-02-19T13:03:54.273 回答
27

我正在使用此代码。您也可以通过 this 获取有关纬度和经度的城市和其他详细信息：

public class getReverseGeoCoding {
    private String Address1 = "", Address2 = "", City = "", State = "", Country = "", County = "", PIN = "";
    
    public void getAddress() {
        Address1 = "";
        Address2 = "";
        City = "";
        State = "";
        Country = "";
        County = "";
        PIN = "";
        
        try {
            
            JSONObject jsonObj = parser_Json.getJSONfromURL("http://maps.googleapis.com/maps/api/geocode/json?latlng=" + Global.curLatitude + ","
                    + Global.curLongitude + "&sensor=true&key=YOUR_API_KEY");
            String Status = jsonObj.getString("status");
            if (Status.equalsIgnoreCase("OK")) {
                JSONArray Results = jsonObj.getJSONArray("results");
                JSONObject zero = Results.getJSONObject(0);
                JSONArray address_components = zero.getJSONArray("address_components");
                
                for (int i = 0; i < address_components.length(); i++) {
                    JSONObject zero2 = address_components.getJSONObject(i);
                    String long_name = zero2.getString("long_name");
                    JSONArray mtypes = zero2.getJSONArray("types");
                    String Type = mtypes.getString(0);
                    
                    if (TextUtils.isEmpty(long_name) == false || !long_name.equals(null) || long_name.length() > 0 || long_name != "") {
                        if (Type.equalsIgnoreCase("street_number")) {
                            Address1 = long_name + " ";
                        } else if (Type.equalsIgnoreCase("route")) {
                            Address1 = Address1 + long_name;
                        } else if (Type.equalsIgnoreCase("sublocality")) {
                            Address2 = long_name;
                        } else if (Type.equalsIgnoreCase("locality")) {
                            // Address2 = Address2 + long_name + ", ";
                            City = long_name;
                        } else if (Type.equalsIgnoreCase("administrative_area_level_2")) {
                            County = long_name;
                        } else if (Type.equalsIgnoreCase("administrative_area_level_1")) {
                            State = long_name;
                        } else if (Type.equalsIgnoreCase("country")) {
                            Country = long_name;
                        } else if (Type.equalsIgnoreCase("postal_code")) {
                            PIN = long_name;
                        }
                    }
                    
                    // JSONArray mtypes = zero2.getJSONArray("types");
                    // String Type = mtypes.getString(0);
                    // Log.e(Type,long_name);
                }
            }
            
        } catch (Exception e) {
            e.printStackTrace();
        }
        
    }
    
    public String getAddress1() {
        return Address1;
        
    }
    
    public String getAddress2() {
        return Address2;
        
    }
    
    public String getCity() {
        return City;
        
    }
    
    public String getState() {
        return State;
        
    }
    
    public String getCountry() {
        return Country;
        
    }
    
    public String getCounty() {
        return County;
        
    }
    
    public String getPIN() {
        return PIN;
        
    }
    
}

有关如何获取 Google Map Api 密钥的更多详细信息

JSON解析器类

public class parser_Json {
    public static JSONObject getJSONfromURL(String url) {

        // initialize
        InputStream is = null;
        String result = "";
        JSONObject jObject = null;

        // http post
        try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(url);
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

        } catch (Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }

        // convert response to string
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString();
        } catch (Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            jObject = new JSONObject(result);
        } catch (JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }

        return jObject;
    }

}

您可以从这个问题中获得更多信息：Get the specific address using latitude and longitude

于 2013-05-13T06:19:02.013 回答
12

试试这个

  List<Address> list = geoCoder.getFromLocation(location
            .getLatitude(), location.getLongitude(), 1);
    if (list != null & list.size() > 0) {
        Address address = list.get(0);
        result = address.getLocality();
        return result;
于 2013-06-03T04:45:43.983 回答
9

只需使用此方法并通过您的纬度，经度。

public static void getAddress(Context context, double LATITUDE, double LONGITUDE) {

//Set Address
try {
    Geocoder geocoder = new Geocoder(context, Locale.getDefault());
    List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
    if (addresses != null && addresses.size() > 0) {



        String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
        String city = addresses.get(0).getLocality();
        String state = addresses.get(0).getAdminArea();
        String country = addresses.get(0).getCountryName();
        String postalCode = addresses.get(0).getPostalCode();
        String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL

        Log.d(TAG, "getAddress:  address" + address);
        Log.d(TAG, "getAddress:  city" + city);
        Log.d(TAG, "getAddress:  state" + state);
        Log.d(TAG, "getAddress:  postalCode" + postalCode);
        Log.d(TAG, "getAddress:  knownName" + knownName);

    }
} catch (IOException e) {
    e.printStackTrace();
}
    return;
}
于 2017-08-18T09:43:54.300 回答
8

试试下面的代码希望对你有用： -

CityAsyncTask cst = new CityAsyncTask(HomeScreenUserLocation.this,
                latitude, longitude);
        cst.execute();

        String lo = null;
        try {
            lo = cst.get().toString();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (ExecutionException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

和异步任务

public class CityAsyncTask extends AsyncTask<String, String, String> {
    Activity act;
    double latitude;
    double longitude;

    public CityAsyncTask(Activity act, double latitude, double longitude) {
        // TODO Auto-generated constructor stub
        this.act = act;
        this.latitude = latitude;
        this.longitude = longitude;
    }

    @Override
    protected String doInBackground(String... params) {
        String result = "";
        Geocoder geocoder = new Geocoder(act, Locale.getDefault());
        try {
            List<Address> addresses = geocoder.getFromLocation(latitude,
                    longitude, 1);
            Log.e("Addresses", "-->" + addresses);
            result = addresses.get(0).toString();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return result;
    }

    @Override
    protected void onPostExecute(String result) {
        // TODO Auto-generated method stub
        super.onPostExecute(result);

    }
}
于 2013-05-30T12:43:26.700 回答
3 
 private class MatchingNearByLocationTask extends
        AsyncTask<Void, Void, Void> 
 {

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        // Showing progress dialog

        progressDialog = new ProgressDialog(mContext);
        progressDialog.setMessage("Loading...");
        progressDialog.setCancelable(true);
        progressDialog.show();

    }

    @Override
    protected Void doInBackground(Void... arg0) {

        jsonStr = getLocationInfo(Latitude, Longitude).toString();
        if (jsonStr != null) {
            Log.i("location--??", jsonStr);

            JSONObject jsonObj;
            try {
                jsonObj = new JSONObject(jsonStr);

                String Status = jsonObj.getString("status");
                if (Status.equalsIgnoreCase("OK")) {
                    JSONArray Results = jsonObj.getJSONArray("results");
                    JSONObject zero = Results.getJSONObject(0);
                    JSONArray address_components = zero
                            .getJSONArray("address_components");

                    for (int i = 0; i < address_components.length(); i++) {
                        JSONObject zero2 = address_components
                                .getJSONObject(i);
                        String long_name = zero2.getString("long_name");
                        JSONArray mtypes = zero2.getJSONArray("types");
                        String Type = mtypes.getString(0);
                        if (Type.equalsIgnoreCase("administrative_area_level_2")) {
                            // Address2 = Address2 + long_name + ", ";
                            String City = long_name;
                            Log.d(" CityName --->", City + "");
                        }
                    }
                }

            }

            catch (JSONException e) {

                e.printStackTrace();
            }

        }

        return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        super.onPostExecute(result);
        // Dismiss the progress dialog
        if (progressDialog.isShowing()) {
            progressDialog.dismiss();
        }

    }

    @Override
    protected void onCancelled() {

        super.onCancelled();
        progressDialog.dismiss();

    }

}




private JSONObject getLocationInfo(double lat, double lng) {

    HttpGet httpGet = new HttpGet(
            "http://maps.googleapis.com/maps/api/geocode/json?latlng="
                    + lat + "," + lng + "&sensor=false");
    HttpClient client = new DefaultHttpClient();
    HttpResponse response;
    StringBuilder stringBuilder = new StringBuilder();

    try {
        response = client.execute(httpGet);
        HttpEntity entity = response.getEntity();
        InputStream stream = entity.getContent();
        int b;
        while ((b = stream.read()) != -1) {
            stringBuilder.append((char) b);
        }
    } catch (ClientProtocolException e) {
    } catch (IOException e) {
    }

    JSONObject jsonObject = new JSONObject();
    try {
        jsonObject = new JSONObject(stringBuilder.toString());
    } catch (JSONException e) {
        e.printStackTrace();
    }

    return jsonObject;
}
于 2014-07-07T11:54:36.540 回答
3

试试这个

var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);

geocoder.geocode(
{'latLng': latlng}, 
function(results, status) {
    if (status == google.maps.GeocoderStatus.OK) {
            if (results[0]) {
                var add= results[0].formatted_address ;
                var  value=add.split(",");

                count=value.length;
                country=value[count-1];
                state=value[count-2];
                city=value[count-3];
                alert("city name is: " + city);
            }
            else  {
                alert("address not found");
            }
    }
     else {
        alert("Geocoder failed due to: " + status);
    }
}

);

于 2017-08-18T08:10:16.760 回答
1

我有新的方法来解决这个问题。在这里，我使用了 google http 服务来获取基于经度和纬度的位置的总信息。您只需要在 url 和您的 api 密钥中传递纬度和经度（例如：latlng=21.1497409, 79.08747970000002 & key=YOUR API KEY）。这是我在ExampleService课堂上的服务

 getService(url) {

    return this.http.get(url).map((data: any) => data.json())

}

你可以把它放在任何你想要的地方，然后从你需要位置数据的组件中调用下面的服务

this._exampleService.getService("https://maps.googleapis.com/maps/api/geocode/json?latlng=21.1497409, 79.08747970000002&key=YOUR API KEY").subscribe(getplaceData => {
            var placeDataDest: any;
            placeDataDest = getplaceData;
            console.log("i got place id yeee " + placeDataDest['results'][0]['place_id']);
            console.log("i got place details yeee " + placeDataDest['results']);
        });

同样找到城市名称....希望您会发现这很有用

于 2017-04-06T06:38:24.687 回答
1

请参考以下代码 

 Geocoder geocoder = new Geocoder(this, Locale.getDefault());
     List<Address> addresses = geocoder.getFromLocation(latitude, longitude, 1);
     String cityName = addresses.get(0).getAddressLine(0);
     String stateName = addresses.get(0).getAddressLine(1);
     String countryName = addresses.get(0).getAddressLine(2);
于 2017-08-12T01:04:32.253 回答
1

尝试使用这个 api：

网址 ": http://maps.googleapis.com/maps/api/geocode/json?latlng= "+String.valueOf(you_lattitude)+","+String.valueOf(your_longitude)

于 2017-08-17T06:44:55.230 回答
0

如果你有一个列表，你可以使用它：

Address address = list.get(0);
String cityname = address.getLocality();
于 2015-09-24T05:57:46.773 回答
0 
 com.alibaba.fastjson.JSONObject jsonObject = com.alibaba.fastjson.JSONObject.parseObject(data);
        if("OK".equals(jsonObject.getString("status"))){
            String formatted_address;
            JSONArray results = jsonObject.getJSONArray("results");
            if(results != null && results.size() > 0){
                com.alibaba.fastjson.JSONObject object = results.getJSONObject(0);
                String addressComponents = object.getString("address_components");
                formatted_address = object.getString("formatted_address");
                Log.e("amaya","formatted_address="+formatted_address+"--url="+url);
                if(findCity){
                    boolean finded = false;
                    JSONArray ac = JSONArray.parseArray(addressComponents);
                    if(ac != null && ac.size() > 0){
                        for(int i=0;i<ac.size();i++){
                            com.alibaba.fastjson.JSONObject jo = ac.getJSONObject(i);
                            JSONArray types = jo.getJSONArray("types");
                            if(types != null && types.size() > 0){
                                for(int j=0;j<ac.size();j++){
                                    String string = types.getString(i);
                                    if("administrative_area_level_1".equals(string)){
                                        finded = true;
                                        break;
                                    }
                                }
                            }
                            if(finded) break;
                        }
                    }
                    Log.e("amaya","city="+formatted_address);
                }else{
                    Log.e("amaya","poiName="+hotspotPoi.getPoi_name()+"--"+hotspotPoi);
                }
                if(hotspotPoi != null) hotspotPoi.setPoi_name(formatted_address);
                EventBus.getDefault().post(new AmayaEvent.GeoEvent(hotspotPoi));
            }
        }

这是一种解析谷歌反馈数据的方法。

于 2017-06-12T06:20:26.080 回答
0

工作代码：

addresses = geocoder.getFromLocation(mMap.getCameraPosition().target.latitude, mMap.getCameraPosition().target.longitude, 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5

                String locality = addresses.get(0).getLocality(); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String subLocality = addresses.get(0).getSubLocality(); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                //String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String address1 = addresses.get(0).getAddressLine(1); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String address2 = addresses.get(0).getAddressLine(2); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
                String city = addresses.get(0).getLocality();
                String state = addresses.get(0).getAdminArea();
                String country = addresses.get(0).getCountryName();
               // String postalCode = addresses.get(0).getPostalCode();
                String knownName = addresses.get(0).getFeatureName();
于 2017-08-18T06:08:03.093 回答
0 
import org.json.JSONObject

fun parseLocation(response: String): GeoLocation? {

val geoCodes by lazy { doubleArrayOf(0.0, 0.0) }

val jObj = JSONObject(response)
if (jObj.has(KEY_RESULTS)) {

    val jArrResults = jObj.getJSONArray(KEY_RESULTS)
    for (i in 0 until jArrResults.length()) {
        val jObjResult = jArrResults.getJSONObject(i)
        //getting latitude and longitude
        if (jObjResult.has(KEY_GEOMETRY)) {
            val jObjGeometry = jObjResult.getJSONObject(KEY_GEOMETRY)

            if (jObjGeometry.has(KEY_LOCATION)) {
                val jObjLocation = jObjGeometry.getJSONObject(KEY_LOCATION)
                if (jObjLocation.has(KEY_LAT)) {
                    geoCodes[0] = jObjLocation.getDouble(KEY_LAT)
                }

                if (jObjLocation.has(KEY_LNG)) {
                    geoCodes[1] = jObjLocation.getDouble(KEY_LNG)
                }
            }
        }

        var administrativeAreaLevel1: String? = null

        //getting city
        if (jObjResult.has(KEY_ADDRESS_COMPONENTS)) {

            val jArrAddressComponents = jObjResult.getJSONArray(KEY_ADDRESS_COMPONENTS)
            for (i in 0 until jArrAddressComponents.length()) {

                val jObjAddressComponents = jArrAddressComponents.getJSONObject(i)
                if (jObjAddressComponents.has(KEY_TYPES)) {

                    val jArrTypes = jObjAddressComponents.getJSONArray(KEY_TYPES)
                    for (j in 0 until jArrTypes.length()) {

                        when (jArrTypes.getString(j)) {

                            VALUE_LOCALITY, VALUE_POSTAL_TOWN -> {
                                return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
                            }

                            ADMINISTRATIVE_AREA_LEVEL_1 -> {
                                administrativeAreaLevel1 = jObjAddressComponents.getString(KEY_LONG_NAME)
                            }

                            else -> {
                            }
                        }
                    }
                }
            }

            for (i in 0 until jArrAddressComponents.length()) {

                val jObjAddressComponents = jArrAddressComponents.getJSONObject(i)
                if (jObjAddressComponents.has(KEY_TYPES)) {

                    val jArrTypes = jObjAddressComponents.getJSONArray(KEY_TYPES)

                    val typeList = ArrayList<String>()
                    for (j in 0 until jArrTypes.length()) {
                        typeList.add(jArrTypes.getString(j))
                    }

                    if (typeList.contains(VALUE_SUBLOCALITY)) {
                        var hasSubLocalityLevel = false
                        typeList.forEach { type ->
                            if (type.contains(VALUE_SUBLOCALITY_LEVEL)) {
                                hasSubLocalityLevel = true

                                if (type == VALUE_SUBLOCALITY_LEVEL_1) {
                                    return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
                                }
                            }
                        }
                        if (!hasSubLocalityLevel) {
                            return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
                        }
                    }
                }
            }
        }

        if (geoCodes.isNotEmpty()) return GeoLocation(administrativeAreaLevel1, geoCodes = *geoCodes)
     }
   }
return null
}

data class GeoLocation(val latitude: Double = 0.0, val longitude: Double = 0.0, val city: String? = null) : Parcelable {

constructor(city: String? = null, vararg geoCodes: Double) : this(geoCodes[0], geoCodes[1], city)

constructor(source: Parcel) : this(source.readDouble(), source.readDouble(), source.readString())

companion object {
    @JvmField
    val CREATOR = object : Parcelable.Creator<GeoLocation> {

        override fun createFromParcel(source: Parcel) = GeoLocation(source)

        override fun newArray(size: Int): Array<GeoLocation?> = arrayOfNulls(size)
    }
}

override fun writeToParcel(dest: Parcel, flags: Int) {
    dest.writeDouble(latitude)
    dest.writeDouble(longitude)
    dest.writeString(city)
}

override fun describeContents() = 0
}
于 2018-05-21T14:09:11.810 回答
0

我在巴西。由于地区细节的原因，这座城市有时会以不同的方式出现。我认为在印度和其他国家也是如此。因此，为了防止错误，我进行了此验证：

private fun getAddress(latLng: LatLng): String {
    // 1
    val geocoder = Geocoder(this)
    val addresses: List<Address>?
    var city = "no"

    try {

        addresses = geocoder.getFromLocation(latLng.latitude, latLng.longitude, 1)

        if (null != addresses && !addresses.isEmpty()) { //prevent from error
             //sometimes the city comes in locality, sometimes in subAdminArea.
            if (addresses[0].locality == null) {

                city = addresses[0].subAdminArea
            } else {
                city = addresses[0].locality
            }

            }
    } catch (e: IOException) {
        Log.e("MapsActivity", e.localizedMessage)
    }

    return city
    }

您还可以检查城市是否返回“否”。如果是这样，则无法获取用户位置。希望能帮助到你。

于 2020-04-30T12:55:58.337 回答