sql-server - 根据子选择的结果更新 SQL 表

Question

当我运行此 SQL 代码时，我收到以下错误消息：

Msg 116, Level 16, State 1, Line 17
Only one expression can be specified in the select list when the subquery 
is not introduced with EXISTS.

我想要的是，每当从具有相同的更新查询中返回任何内容时，它都会使用of + 1AgreementNo, ElementStartDate and DateSeqNo更新这些重复记录之一，这将删除重复项。ElementStartDate

Update [WASP_Mart_EmbassyActuarial].[dbo].[tblARM_OmegaSource]  
SET ElementStartDate = ElementStartDate + 1  
WHERE AgreementNo IN   
    (SELECT
        count(*) as [Count],
        [AgreementNo],
        [ElementStartDate],
        [DateSeqNo],
        getdate() as Today  
     FROM [WASP_Mart_EmbassyActuarial].[dbo].[tblARM_OmegaSource]   
     GROUP BY  
         [AgreementNo],
         [ElementStartDate],
         [DateSeqNo]  
     HAVING COUNT(*) = 2) 

Answer 1

子查询返回多于一列。您不能使用 in Operator 比较多个列。

试试下面的查询：

Update [WASP_Mart_EmbassyActuarial].[dbo].[tblARM_OmegaSource]  
SET ElementStartDate = ElementStartDate + 1  
WHERE AgreementNo IN   
 ( SELECT [AgreementNo] 
   FROM [WASP_Mart_EmbassyActuarial].[dbo].[tblARM_OmegaSource]   
   GROUP BY  [AgreementNo] -- OR [AgreementNo],[ElementStartDate],[DateSeqNo]
   HAVING COUNT(*) = 2) 

Answer 2

在 的分区中分配行号AgreementNo, ElementStartDate, DateSeqNo并更新行号大于 1 的那些行：

WITH ranked AS (
  SELECT
    ElementStartDate,
    rn = ROW_NUMBER() OVER (PARTITION BY AgreementNo, ElementStartDate, DateSeqNo
                                ORDER BY (SELECT 1))  -- actual order probably
                                                      -- doesn't matter here
  FROM WASP_Mart_EmbassyActuarial.dbo.tblARM_OmegaSource
)
UPDATE ranked
SET ElementStartDate = ElementStartDate + rn - 1
WHERE rn > 1
;

这种方法可以处理一个组中有两个以上重复的案例，当然，如果有很多重复，它可能会开始产生新的。

Answer 3

也许试试这个：

Update [WASP_Mart_EmbassyActuarial].[dbo].[tblARM_OmegaSource]  
SET ElementStartDate = ElementStartDate + 1  
WHERE AgreementNo IN   
 (SELECT 
      AgreementNo 
  FROM [WASP_Mart_EmbassyActuarial].[dbo].[tblARM_OmegaSource]   
  GROUP BY 
      [AgreementNo],
      [ElementStartDate],
      [DateSeqNo]
  HAVING COUNT(*) = 2)