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我正在尝试使用 Deezer Android API 播放音乐，遵循 SDK 的示例代码。我只得到 30 年代的预览，从来没有流。以下是返回的输出片段：

{"id":"72306644","readable":true,"title":"Aura","link":"http:\/\/www.deezer.com\/track\/72306644","duration":236,"track_position":1,"disk_number":1,"rank":426293,"preview":"http:\/\/cdn-preview-e.deezer.com\/stream\/e0c84057c93e3cad84317d768413c0e3-0.mp3","stream":false,"artist"
{"id":"75491","name":"Lady GaGa","type":"artist"},"type":"track"}

认证成功。我使用高级 + 帐户登录。我做错了什么或错过了一步吗？

它现在似乎正在返回流 - 也许只是需要时间将帐户升级到高级+。然而，它没有播放流。即没有播放音乐。

它非常接近 SDK 中的示例代码并基于在线文档：首先创建播放器：

deezerConnect = new DeezerConnectImpl( parentActivity, APP_ID );
try {
   player = new DefaultPlayerFactory( parentActivity.getApplication(), 
   deezerConnect, new WifiOnlyNetworkStateChecker() ).createPlayer();
} catch (Exception e) {
   handleError( e );
}

然后打个电话去听歌...

private void searchTracks(Album album) {
   long albumId = album.getId();
   Bundle bundle = new Bundle();
   bundle.putString( "nb_items", "30");
   DeezerRequest request = new DeezerRequest( "album/"+albumId+"/tracks", bundle );
   request.setId( String.valueOf( albumId ) );
   deezerConnect.requestAsync( request, trackHandler );
}

然后在 trackHandler 中解析结果并使用 gson 创建一个轨道对象后，它会尝试播放轨道：

private void playTrack( Track track ) {
   if( player.getPlayerState() != PlayerState.STARTED ) {
      player.stop();
   }//if
   Log.d(TAGNAME, "Init track:" + track.getId() +":"+ deezerConnect.getAccessToken() +":"+   
   track.getStream() );

   if( track.hasStream() ) {
      player.init( track.getId(), track.getStream());
   } else {
      Log.d( TAGNAME,"Playing track preview:" + track.getId() );
      player.init( track.getId(), track.getPreview() );
   }//else

   player.setPlayerProgressInterval(1000);
   player.play();
}

如果有帮助，以下是响应输出的一些片段：

响应：{"data":[{"id":"17519569","可读":true,"title":"Dirty Paws","link":"http://www.deezer.com/track/17519569 ","duration":278,"track_position":1,"disk_number":1,"rank":399040,"preview":"http://cdn-preview-d.deezer.com/stream/def7161be8ee42ecb20036a136ad0cf6-2 .mp3","stream":" ....这里的十六进制数字长字符串... ","artist":{"id":"1581786","name":"Of Monsters And Men","type ":"艺术家"},"类型":"曲目"}

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