a包含索引及其出现。现在需要使用汉明权重更改索引，以便将具有相同汉明权重的索引相加。如何进行汉明权重索引？在 Matlab 中有任何现成的命令吗？
>> a=[1,2;2,3;5,2;10,1;12,2]
1 2
2 3
5 2
10 1
12 2
13 8
>> dec2bin(a(:,1))
ans =
0001
0010
0101
1010
1100
1101
目标：通过汉明权重索引事物
HW Count
1 5 (=2+3)
2 5 (=2+1+2)
3 8 (=8)
你可以这样做：
a = [1,2;2,3;5,2;10,1;12,2;13,8]
需要添加以下行，以考虑也为零的hammingweight：
if nnz(a(:,1)) == numel(a(:,1)); a = [0,0;a]; end
% or just
a = [0,0;a]; %// wouldn't change the result
获取索引
rowidx = sum( de2bi(a(:,1)), 2 )
得到总和
sums = accumarray( rowidx+1, a(:,2) ) %// +1 to consider Hammingweight of zero
得到 Hammingweight 向量
HW = unique(rowidx)
返回：
rowidx =
1
1
2
2
2
3
sums =
5
5
8
一起：
result = [HW, sums]
%or
result = [unique(rowidx), accumarray(rowidx+1,a(:,2))]
result =
0 0
1 5
2 5
3 8
如果您对线路感到困扰，请将0 0其过滤掉
result(sum(result,2)>0,:)
结果a = [0,2;2,3;5,2;10,1;12,2;13,8]将是：
result =
0 2
1 3
2 5
3 8
尝试这个 -
a = [1 2
2 3
5 2
10 1
12 2
13 8]
HW = dec2bin(a(:,1)) - '0';
out = accumarray(sum(HW,2), a(:,2), [], @sum);%%// You don't need that "sum" option it seems, as that's the default operation with accumarray
final_out = [unique(sum(HW,2)) out]
输出 -
a =
1 2
2 3
5 2
10 1
12 2
13 8
final_out =
1 5
2 5
3 8