1

这是我的场景:

我有一个build.bat

call tools\nant-0.92\bin\nant.exe -buildfile:deploy.build %* -logfile:deploy_NAnt.log

部分deploy.build持有:

<project 
    name="EdpClient" 
    basedir="." default="build" 
    xmlns="http://nant.sf.net/release/0.92/nantContrib.xsd">
        <!--INIT -->
        ...
        <property name="version" value="1.48.0.4" />
        ...
        <!--RELEVANT TARGET-->
        <target name="BuildProductionApplication" description="Build">
            <property 
                name="publishFolderParameter" 
                value="/p:PublishDir=${productionPublishFolder}" />
            <echo message="Building..." />  
            <exec 
                program="${msbuildExe}" 
                workingdir="." verbose="true">
                    <arg value="${projectFile}" />
                    <arg value="/target:Clean;Publish" />
                    <arg value="${publishFolderParameter}" />
                    <arg value="/property:ApplicationVersion=${version}" />
                    <arg value="/property:PublisherName=&quot;${publisherName}&quot;" />
            </exec>
            <echo message="Built" />
        </target>
    ...
</project>

现在我的问题是:

  • 我如何调用"build.bat -version 1.48.0.4"和替换结构中的参数?
  • 如果-version未提供参数,脚本应该在命令行中返回某种味精?

感谢所有这些帮助!

4

1 回答 1

2

我就是这样做的:

deploy.build我更改的文件中:

<property name="version" value="1.48.0.4" />

到:

<property name="version" value="${arg.version}" />

这就是 build.bat (batch) 现在的样子:

@ECHO OFF
IF %1.==. GOTO ERROR
ECHO:BUILDING VERSION: %1 ...
CALL tools\nant-0.92\bin\nant.exe -buildfile:deploy.build -D:arg.version=%1 -logfile:deploy_NAnt.log
GOTO END
:ERROR
ECHO.
ECHO Please provide the version parameter (eg. "deploy 1.1.1.1")
ECHO.
GOTO END
:END

现在我可以调用build 1.48.0.4命令了。它适合我的所有需求。

于 2014-04-07T10:02:54.007 回答