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我的代码得到了错误的答案

n 是变量的数量，公式是包含子句的列表

给定一个包含“n”个变量和在列表“公式”中编码的子句的 SAT 实例，如果该实例可满足，则返回“可满足”，否则返回“不可满足”。'formula' 的每个元素代表一个子句，是一个整数列表，其中整数 i 表示文字 Xi 存在于子句中，整数 -i 表示文字 ~Xi 存在于子句中。例如，子句“X1 v ~X11 v X7”用列表 [1, -11, 7] 表示。

import itertools
n = 4 
formula = [[1, -2, 3], [-1, 3], [-3], [2, 3]]


booleanValues = [True,False] * n

allorderings = set(itertools.permutations(booleanValues, n)) #create possible combinations of variables that can check if formula is satisfiable or not

print(allorderings)

for potential in allorderings:
    l = [] #boolean value for each variable / different combination for each iteration
    for i in potential:
        l.append(i)
    #possible = [False]*n
    aclause = []
    for clause in formula:
        something = []
        #clause is [1,2,3]
        for item in clause:
            if item > 0:
                something.append(l[item-1]) 
            else:
                item = item * -1
                x = l[item-1]
                if x == True:
                    x = False
                else:
                    x = True
                something.append(x)
        counter = 0
        cal = False
        for thingsinclause in something:
            if counter == 0:
                cal = thingsinclause
                counter = counter + 1
            else:
                cal = cal and thingsinclause
                counter = counter + 1

        aclause.append(cal)

    counter2 = 0
    formcheck = False
    for checkformula in aclause:
        if counter2 == 0:
            formcheck = checkformula
            counter2 = counter2 + 1
        else:
            formcheck = formcheck or checkformula
    print("this combination works", checkformula)
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1 回答 1

0

Here is a corrected version:

import itertools
n = 4 
formula = [[1, -2, 3], [-1, 3], [-3], [2, 3]]

allorderings = itertools.product ([False, True], repeat = n)

for potential in allorderings:
    print ("Initial values:", potential)
    allclauses = []
    for clause in formula:
        curclause = []
        for item in clause:
            x = potential[abs (item) - 1]
            curclause.append (x if item > 0 else not x)
        cal = any (curclause)
        allclauses.append (cal)
    print ("Clauses:", allclauses)
    formcheck = all (allclauses)
    print ("This combination works:", formcheck)

Points to consider:

  1. Instead of introducing some complex — and also wrong — logic to find the conjunction and disjunction, you can use any and all. That's cleaner and less prone to bugs.

  2. The natural object to loop over is itertools.product([False, True], repeat = n), that is, the set [False, True] of possible boolean values raised to the power of n. In other words, the Cartesian product of n copies of [False, True]. Here is the documentation for itertools.product.

  3. I introduced a bit more output to see how things are going. Here is the output I get with Python3 (Python2 adds parentheses but prints essentially the same):

Initial values: (False, False, False, False)
Clauses: [True, True, True, False]
This combination works: False
Initial values: (False, False, False, True)
Clauses: [True, True, True, False]
This combination works: False
Initial values: (False, False, True, False)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (False, False, True, True)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (False, True, False, False)
Clauses: [False, True, True, True]
This combination works: False
Initial values: (False, True, False, True)
Clauses: [False, True, True, True]
This combination works: False
Initial values: (False, True, True, False)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (False, True, True, True)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (True, False, False, False)
Clauses: [True, False, True, False]
This combination works: False
Initial values: (True, False, False, True)
Clauses: [True, False, True, False]
This combination works: False
Initial values: (True, False, True, False)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (True, False, True, True)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (True, True, False, False)
Clauses: [True, False, True, True]
This combination works: False
Initial values: (True, True, False, True)
Clauses: [True, False, True, True]
This combination works: False
Initial values: (True, True, True, False)
Clauses: [True, True, False, True]
This combination works: False
Initial values: (True, True, True, True)
Clauses: [True, True, False, True]
This combination works: False
于 2014-04-04T08:47:08.473 回答