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作为我们课程作业的一部分，我自己和班上的另一个人必须制作一个猜谜游戏，其中会生成一个介于 1 到 100 之间的随机数，并且用户最多有 6 次猜测来尝试猜测这个数字。我还必须创建一个“会话”，用户可以在其中输入他们的姓名，并将他们的结果存储到一个文本文件中。我已经让它工作到他们可以玩游戏并成功输入他们的名字的地步，但是如果您选择要再次玩的选项，它会显示“处理完成”并退出程序。非常感谢您的帮助，这是我到目前为止所拥有的；

代码：

import java.util.Random; //importing the Random class
import java.util.Scanner; //importing the Scanner class

/* Author Laura Brown 28/02/2014 */

public class TheGuessingGame 
{ 
 public static void main(String[] args) 
 { 

 Random generator = new Random(); //creates a random number between 1-100
 int TARGET = generator.nextInt(100) + 1; //establishes the target number

 int guess; 
 int count = 0;
 String userName;
 String another = "y";
 Boolean flag = false;
 Boolean anotherFlag = true;

 Scanner consoleIn = new Scanner(System.in); //creating a new Scanner object
 Scanner name = new Scanner(System.in); //creating a new Scanner object

 System.out.print("Hello! Please enter your name:\n"); //asking for user input
 userName = name.nextLine();

 System.out.print("Hello "+ userName+ ", and welcome to the game!\n");

 System.out.print("Can you guess what it   is?\n");

    do { //beginning the loop
    guess = consoleIn.nextInt(); 
    count++; 

    if (guess > TARGET) 
    System.out.print("Sorry - Your guess is too high \n"); 
    else 
    if (guess < TARGET)
    System.out.print("Sorry - Your guess is too low \n"); 
    }


    while(guess != TARGET && count < 6);

    if(guess == TARGET) {
    System.out.println("Congratulations! - You found it!"); 
    System.out.println();
    }

    else {
    System.out.println("Sorry - You have used all 6 guesses");
    }

    System.out.println();
    System.out.println("Would you like to guess again? (yes/no)");
    another = consoleIn.next();

    }
}
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2 回答 2

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public static void main(String[] args) 
 { 

 Random generator = new Random(); //creates a random number between 1-100

 int guess; 
 int count = 0;
 int Target;
 String userName;
 String another = "y";
 Boolean flag = false;
 Boolean anotherFlag = true;

 Scanner consoleIn = new Scanner(System.in); //creating a new Scanner object
 Scanner name = new Scanner(System.in); //creating a new Scanner object

 System.out.print("Hello! Please enter your name:\n"); //asking for user input
 userName = name.nextLine();

 System.out.print("Hello "+ userName+ ", and welcome to the game!\n");

 while (another.equalsIgnoreCase("y")) // this will check if your user input "another" 
 {
 TARGET = generator.nextInt(100) + 1; //establishes the target number
 System.out.print("Can you guess what it   is?\n");


    do { //beginning the loop
    guess = consoleIn.nextInt(); 
    count++; 

    if (guess > TARGET) 
    System.out.print("Sorry - Your guess is too high \n"); 
    else 
    if (guess < TARGET)
    System.out.print("Sorry - Your guess is too low \n"); 
    }


    while(guess != TARGET && count < 6);

    if(guess == TARGET) {
    System.out.println("Congratulations! - You found it!"); 
    System.out.println();
    }

    else {
    System.out.println("Sorry - You have used all 6 guesses");
    }

    System.out.println();
    System.out.println("Would you like to guess again? (yes/no)");
    another = consoleIn.next();
    consoleIn.nextLine();

    }
 }
}

在另一个循环中添加以循环整个游戏过程。并将随机生成方法降低到循环内部以重新生成一个新数字。试试看。无论如何，我添加了另一行 consoleIn.nextLine(); 在用户输入清除 .next() 方法的回车缓冲区后。

于 2014-04-03T09:12:39.073 回答
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您需要添加另一个循环。从风格上讲，我会避免使用 do...while 循环，因为它们很难阅读。我已经包含了一个以更传统的方式完成的 while 循环，以向您展示它们是多么幸福性感。

while(anotherFlag)
{
    TARGET = generator.nextInt(100) + 1; //establishes the target number

    System.out.print("Can you guess what it   is?\n");

    do 
    {   //beginning the loop
        guess = consoleIn.nextInt(); 
        count++; 

        if (guess > TARGET) 
        System.out.print("Sorry - Your guess is too high \n"); 
        else 
        if (guess < TARGET)
        System.out.print("Sorry - Your guess is too low \n"); 
    }
    while(guess != TARGET && count < 6);

    if(guess == TARGET) {
        System.out.println("Congratulations! - You found it!"); 
        System.out.println();
    }
    else 
    {
        System.out.println("Sorry - You have used all 6 guesses");
    }

    System.out.println();
    System.out.println("Would you like to guess again? (yes/no)");

    another = consoleIn.next(); 


}

以上将无法完全工作，如果用户输入“否”，则需要将 anotherFlag 设置为 false。这应该是一个相对简单的练习，但是上面的练习会让程序一遍又一遍地循环。

于 2014-04-03T09:12:48.313 回答