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我们在 SharePoint 2010 环境中使用文档库。文档库中大约有 200 个文档已被识别（基于位置 - 英格兰和员工类型 - FT），现在我必须将这 200 个文档的内容类型更改为新的内容类型“新 FT”。我为此目的使用以下电源外壳代码-

$webUrl  = "http://www.site.com/sites/Library/"
$web = Get-SPWeb -Identity $webUrl
$list = $web.Lists["CURRENT FTE"]
$spQuery = New-Object Microsoft.SharePoint.SPQuery
$spQuery.ViewAttributes = "Scope='Recursive'";
$spQuery.ListItemCollectionPosition = $listItems.ListItemCollectionPosition

    foreach($item in $listItems)
    {
        $lookup  = [Microsoft.SharePoint.SPFieldLookupValue]$item["ROLE"];   
        $role = $lookup.LookupValue;

        $EMPTYPE  = $item["EMP TYPE"]

        $lookup4  = [Microsoft.SharePoint.SPFieldLookupValue]$item["Location"];   
        $LOCATION = $lookup4.LookupValue;

        $ContentTypeName = $item.ContentType.Name
        $ContentTypeID = $item.ContentType.Id

         if ($LOCATION -eq "England") 
         {
            if($EMPTYPE -eq "FT")
            {   
                #CheckList - 1
                Write-Output  "ID - $($item.id) " 
                Write-Output  "Name - $($item.name)"
                Write-Output  "Role - $($role) "  
                Write-Output  "emptype - $($EMPTYPE) "
                Write-Output  "location - $($LOCATION) "
                Write-Output  "Content Type Name - $($ContentTypeName) "
                Write-Output  "Content Type ID - $($ContentTypeID) "
                Write-Output "  "

                $newct = $list.ContentTypes["New FT"]
                $newctid = $newct.ID

                    If (($newct -ne $null) -and ($newctid -ne $null))
                        {
                            $item["ContentTypeId"] = $newctid
                            $item.Update()

                            $newContentTypeName = $item.ContentType.Name
                            $newContentTypeID = $item.ContentType.Id

                            #CheckList - 2
                            Write-Output  "ID - $($item.id) " 
                            Write-Output  "Name - $($item.name)"
                            Write-Output  "Role - $($role) "  
                            Write-Output  "emptype - $($EMPTYPE) "
                            Write-Output  "location - $($LOCATION) "
                            Write-Output  "Content Type Name - $($newContentTypeName) "
                            Write-Output  "Content Type ID - $($newContentTypeID) "
                            Write-Output "  "
                            }



            }
        }

    }

现在代码识别每个文档/记录，然后打印 CheckList - 1 中列出的详细信息，然后我进行更新并尝试在 CheckList - 2 中打印新的更新值 - 但问题是 CheckList -2 不打印更新的内容类型和更新的内容类型 ID ($newContentTypeName, $newContentTypeID)。

我在这里做错了什么吗，请指教！（如有必要，请随时更新代码）

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1 回答 1

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好吧，在上面的“Yevgeniy.Chernobrivets”评论的帮助下，我能够使所有字段都出现在 CheckList 中 - 2. 根据评论，我必须执行以下操作 -

 $updateItem = $list.GetItemById($item.ID); 
$contentTypeID = $updateItem.ContentType.Id
$contentTypeName = $updateItem.ContentType.Name
于 2014-04-03T17:28:56.607 回答