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您好我正在尝试使用 wifimanager api 将我的应用程序连接到特定的接入点。就目前而言,我有一个我所在地区所有接入点的列表,从这个列表中我将它们存储在一个数组中并选择要连接的一个。但现阶段是连接不上。有人能帮我吗 。

(这是我试图连接的开放网络。)这是我的代码:

public void WifiConfiguration(){
    try {
        ScanResult networkData = getIntent().getParcelableExtra("networkData");

        WifiManager wifiManager = (WifiManager)getApplicationContext().getSystemService(Context.WIFI_SERVICE);
        String networkPassWord = "";

        WifiConfiguration conf = new WifiConfiguration();
        conf.SSID = "\"" + networkData.SSID + "\"";
        conf.BSSID = "\"" + networkData.BSSID + "\"";
        conf.hiddenSSID = true;
        conf.wepKeys[0] = "\"" + networkPassWord + "\""; 
        conf.wepTxKeyIndex = 0; 
        conf.status = WifiConfiguration.Status.ENABLED;        
        conf.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.TKIP);
        conf.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.CCMP);
        conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.WPA_PSK);
        conf.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.TKIP);
        conf.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.CCMP);
        conf.allowedProtocols.set(WifiConfiguration.Protocol.RSN);

        conf.preSharedKey = "\""+ networkPassWord +"\"";

        //conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);

        Log.d(TAG, "Initialising WIFI Manager");

        int id = wifiManager.addNetwork(conf);
        Log.d(TAG, "conf.SSID: "+conf.SSID);
        Log.d(TAG, "id: "+id);
        wifiManager.disconnect();
        wifiManager.enableNetwork(id, true);
        wifiManager.reconnect();       

        Log.d(TAG, "Should be connected....");

    } catch (Exception e) {

        Log.d(TAG, e.toString());
    }

}
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1 回答 1

0
    conf.SSID = "\"" + networkData.SSID + "\"";
    conf.BSSID = "\"" + networkData.BSSID + "\"";

BSSID 不需要用双引号括起来,只需 SSID。

于 2014-06-10T21:53:08.427 回答