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我正在尝试使用 NodeJs 和 Formidable 制作图像/文件上传表单。我没有使用快递。简直厉害。但无论如何，我尝试了最常见的强大脚本，但没有一个有效。我的代码与本教程中的代码基本完全相同：http: //justinkjchang.wordpress.com/2013/11/08/image-uploader -using-node-js/ 周围有很多这样的教程，我在一些书籍或视频中看到几乎完全相同的东西，它们似乎都有效，除了我的。我已经安装了强大的，我有最新版本，还有 Node.js。我也在mac上。当我尝试上传时，它会通过 form.parse 和所有内容，但是当它尝试写入文件时，它会抛出此错误：

/Users/USER/Documents/Node/requestHandlers.js:42
    fs.rename(files.upload.path, "/tmp/test.png", function (error) {
                          ^
TypeError: Cannot read property 'path' of undefined

我是 Nodejs 的新手，所以任何形式的帮助都会很好。我也尝试过 file.write ，它仍然抛出同样的错误。任何帮助将不胜感激（：

更新了代码：

var exec = require("child_process").exec;
var qs = require("querystring"),
fs = require("fs"),
formidable = require("formidable"),
url = require( "url" );

function start(response, request) {
/*
var fileName = "start.html"
var localPath = __dirname;
var mimeType = "text/html";
var name = localPath + "/" + fileName;
getFile(name, response, mimeType);
console.log("Request handler 'start' was called.");
console.log("Serving File: " + name);
*/
var body = '<html>'+
    '<head>'+
    '<meta http-equiv="Content-Type" '+
    'content="text/html; charset=UTF-8" />'+
    '</head>'+
    '<body>'+
    '<form action="/upload" enctype="multipart/form-data" '+
    'method="post">'+
    '<input type="file" name="upload" multiple="multiple">'+
    '<input type="submit" value="Upload file" />'+
    '</form>'+
    '</body>'+
    '</html>';

console.log( "Request for 'start' is called." );

response.writeHead( 200, { "Content-Type" : "text/html" } );
response.end( body );
}

function upload(response, request) {
console.log("Request handler 'upload' was called.");
console.log( "Preparing upload" );

var form = new formidable.IncomingForm();

form.parse(request, function(error, fields, files){
    if(error){
        console.log(error);
        console.log("Dun Goofed");
    }
    console.log("parsing done");
    fs.rename(files.upload.path, "/tmp/test.png", function (error) {
        if (error) {
            fs.unlink("/tmp/test.png");
            fs.rename(files.upload.path, "/tmp/test.png");
        }
    });
    /* fs.rename(files.upload.path, "/tmp/test.png", function(err){
        if(err){
            fs.unlink("/tmp/test.png");
            fs.rename(files.upload.path, "/tmp/test.png");
        }
    }); */
    response.writeHead(200, {"Content-Type": "text/plain"});
    response.write("Received image: <br/>");
    response.write("<img src='./show' />");
    response.end(); 
});
}


exports.start = start;
exports.upload = upload;
//exports.show = show;

我省略了一些部分，因为它们与文件上传无关，请原谅评论，只是旧代码。我也没有 /show 功能，因为我暂时删除了它。此外，这是我在控制台中遇到的错误。错误之一是因为上传取消。在我输入我要上传的文件后，浏览器只是在那里坐了一会儿，等待服务器的请求，在控制台中，它只是在 form.parse 之前停止，然后坐在那里什么也不做大约一分钟，然后它推出了所有的错误。

Web Server started on 127.0.0.1:8888
Request for / received.
About to route a request for /
Served a request for /
Request for 'start' is called.
Request for /upload received.
Received POST data chunk
About to route a request for /upload
Served a request for /upload
Request handler 'upload' was called.
Preparing upload

成功执行到这里。然后浏览器等待一会，然后要么弹出没有收到数据，要么网页不可用，然后控制台出现这些错误。

{}
[Error: Request aborted]
Dun Goofed
parsing done

/Users/USER/Documents/Node/requestHandlers.js:50
    fs.rename(files.upload.path, "/tmp/test.png", function (error) {
                          ^
TypeError: Cannot read property 'path' of undefined
at /Users/USER/Documents/Node/requestHandlers.js:50:31
at IncomingForm.<anonymous>    (/Users/USER/node_modules/formidable/lib/incoming_form.js:89:9)
at IncomingForm.EventEmitter.emit (events.js:95:17)
at IncomingForm._error (/Users/USER/node_modules/formidable/lib/incoming_form.js:272:8)
at IncomingMessage.<anonymous>     (/Users/USER/node_modules/formidable/lib/incoming_form.js:107:12)
at IncomingMessage.EventEmitter.emit (events.js:92:17)
at abortIncoming (http.js:1911:11)
at Socket.serverSocketCloseListener (http.js:1923:5)
at Socket.EventEmitter.emit (events.js:117:20)
at TCP.close (net.js:465:12)
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1 回答 1

1

我也有同样的问题。

删除 request.setEncoding("utf8");server.js中的代码

像这样：

function start(route, handler) {
    http.createServer(function(request, response) {
        var postData = "";
        var pathname = url.parse(request.url).pathname;
        route(handler, pathname, response, request);

    }).listen(8889);
}
于 2014-03-30T14:04:22.230 回答