perl - Perl - 通过数组哈希循环

Question

my %aggrs_by_node = (
    node1 => ['a1_1','a1_2'],
    node2 => ['a2_1','a2_2','a2_3'],
    hello => ['ah_1','ah_2','ah_3'],
    node3 => ['a3_1','a3_2','a3_3','a3_4'],
);

有人对我如何在避免 key 的同时循环遍历此哈希中的所有数组元素有任何建议hello吗？

Iteration 1 = a1_1
Iteration 2 = a2_1
Iteration 3 = a3_1
Iteration 4 = a1_2
Iteration 5 = a2_2
Iteration 6 = a3_2
Iteration 7 = a1_1
Iteration 8 = a2_3

ETC...

Answer 1

这个简短的程序可以满足您的要求。它将索引哈希保存到每个数组中。

我在数组中使用了一个单独的散列键排序列表，@keys因为直接从散列中获取它们会导致不可预知的顺序，并且看起来您需要按特定顺序输出。

use strict;
use warnings;

my %aggrs_by_node = (
  node1 => ['a1_1','a1_2'],
  node2 => ['a2_1','a2_2','a2_3'],
  hello => ['ah_1','ah_2','ah_3'],
  node3 => ['a3_1','a3_2','a3_3','a3_4'],
);

my %indices = map { $_ => 0 } keys %aggrs_by_node;
delete $indices{hello};
my @keys = sort keys %indices;

for my $iter (1 .. 20) {
  my $key = $keys[($iter - 1) % @keys];
  my $val = $aggrs_by_node{$key}[$indices{$key}];
  $indices{$key} = ($indices{$key} + 1) % @{ $aggrs_by_node{$key} };
  printf "Iteration %d = %s\n", $iter, $val;
}

输出

Iteration  1 = a1_1
Iteration  2 = a2_1
Iteration  3 = a3_1
Iteration  4 = a1_2
Iteration  5 = a2_2
Iteration  6 = a3_2
Iteration  7 = a1_1
Iteration  8 = a2_3
Iteration  9 = a3_3
Iteration 10 = a1_2
Iteration 11 = a2_1
Iteration 12 = a3_4
Iteration 13 = a1_1
Iteration 14 = a2_2
Iteration 15 = a3_1
Iteration 16 = a1_2
Iteration 17 = a2_3
Iteration 18 = a3_2
Iteration 19 = a1_1
Iteration 20 = a2_1