0

该程序为重做引发错误我该如何解决

use strict;
use warnings;
use Switch::Plain;

my %data = (0 => "Enter the number",1 => "UPC",2 => "URL", 3 => "Elastic Search", 4 => "API", 5 => "MONGO", 6 => "TSV", 7 => "SQL", 8 => "JSON", 9 => "Enter the correct value");
my $input = "Enter the number:";


sub input(){
    print "Choose You Input Method"."\n";
    print "1.UPC"."\n";
    print "2.URL"."\n";
    print "3.Elastic Search"."\n";
    print $input;
    PROMPT: {
    chomp(my $input = <>);
     nswitch($input){
        case 1 : {print "UPC"."\n"}
        case 2 : {print "URL"."\n"}
        case 3 : {print "Elastic Search"."\n"}
        default: {"Enter the correct value"; redo PROMPT }

      }


}
}

input();

my $pinput = "Enter the number:";
sub pinput(){
    print "Choose Your Process Method"."\n";
    print "1.API"."\n";
    print "2.Mongo"."\n";
    print $pinput;
    $pinput = <>;
    chomp($pinput);
    nswitch($pinput){
       case 1 : {print "API"."\n"}
       case 2 : {print "MONGO"."\n"}
       default : {print "Enter the correct value"."\n"}
}
}

pinput();

抛出的错误是

Argument "" isn't numeric in numeric eq (==) at framework.pl line 21, <> line 1

这个想法是如果使用的输入有任何不匹配，例如如果用户键入空值或 4，则重复子例程？

请帮我解决？

4

2 回答 2

2

0您可以通过添加或乘以将输入转换为数字1，

$pinput = <> *1;

或转换后chomp

$pinput *= 1;
于 2014-03-27T12:46:26.590 回答
0

查看How do I create a switch or case statement?

如果您使用的是 5.10 或更高版本，则可以使用内置方法来执行此操作。然后一种解决方案是将您匹配的内容视为字符串而不是数字：

use 5.010;

use strict;
use warnings;

print "Choose You Input Method"."\n";
print "1.UPC"."\n";
print "2.URL"."\n";
print "3.Elastic Search"."\n";

PROMPT: {
    chomp(my $input = <>);
    given ( $input ) {
        when( '1' )  { say "UPC" }
        when( '2' )  { say "URL" }
        when( '3' )  { say "Elastic Search" }
        default      { print "Enter the correct value"; redo PROMPT }
    };
}
于 2014-03-28T04:05:06.767 回答