9

Using the requests python lib, I make a GET request, and handle Timeout exceptions (as well as other exceptions I don't show here) like

import requests
timeout1=20
timeout2=40

try:
    #first attempt
    resp = requests.get(base_url+resource, params=payload, headers=headers,
    timeout=timeout1)
except requests.exceptions.Timeout:
    #timed out, retry once
    try:
       resp = requests.get(base_url+resource, params=payload, headers=headers,
       timeout=timeout2)
       return resp.json()
    except requests.exceptions.RequestException as e:
       #Still failed; return error code
       return -1

This works fine most of the time, however sometimes my program just completely exits with the error socket.timeout: timed out, instead of throwing the requests.exceptions.Timeout and this being caught and dealt with.

Why is the requests lib behaving like this? How should I handle this?

4

2 回答 2

2

回答：

try:
    data = sock.recv(256)
except socket.timeout:
    data="NO RESPONSE"

它不会退出！

于 2014-09-08T19:18:15.413 回答
2

我认为这是请求使用的 urllib3 的问题：

https://github.com/kennethreitz/requests/issues/1236

你必须抓住那个 socket.timeout 错误。（基于 jb 在Correct way to try/except using Python requests 模块的评论？）

于 2016-02-19T07:59:31.047 回答