5

我有以下声明:

 PreparedStatement prpStat = conn
                    .prepareStatement("SELECT * FROM natperson WHERE name LIKE ?");
            prpStat.setString(1, "A");
            ParameterMetaData pmd = prpStat.getParameterMetaData();
            ResultSet rs = prpStat.executeQuery();

prpStat.getParameterMetaData();当我使用 ojdbc7.jar执行该方法时,我得到以下异常。使用 ojdbc6 时不会抛出异常。

java.sql.SQLSyntaxErrorException: ORA-00904: "NAMEIKE": ungültiger Bezeichner

    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:450)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:392)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:385)
    at oracle.jdbc.driver.T4CTTIfun.processError(T4CTTIfun.java:938)
    at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:655)
    at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:249)
    at oracle.jdbc.driver.T4C8Odscrarr.doODNY(T4C8Odscrarr.java:96)
    at oracle.jdbc.driver.T4CPreparedStatement.doDescribe(T4CPreparedStatement.java:719)
    at oracle.jdbc.driver.OracleStatement.describe(OracleStatement.java:4223)
    at oracle.jdbc.driver.OracleResultSetMetaData.<init>(OracleResultSetMetaData.java:52)
    at oracle.jdbc.driver.OracleStatement.getResultSetMetaData(OracleStatement.java:4206)
    at oracle.jdbc.driver.OraclePreparedStatement.getMetaData(OraclePreparedStatement.java:4603)
    at oracle.jdbc.driver.OraclePreparedStatementWrapper.getMetaData(OraclePreparedStatementWrapper.java:1510)
    at oracle.jdbc.driver.OracleParameterMetaData.getParameterMetaData(OracleParameterMetaData.java:70)
    at oracle.jdbc.driver.OraclePreparedStatement.getParameterMetaData(OraclePreparedStatement.java:11621)
    at oracle.jdbc.driver.OraclePreparedStatementWrapper.getParameterMetaData(OraclePreparedStatementWrapper.java:1552)
    at com.agfa.jdbc.test.JDBCTester.main(JDBCTester.java:45)

任何想法如何解决这个问题?

4

2 回答 2

6

Oracle 错误解决了 LIKE 运算符导致解析器出现问题的问题:
错误 18590786

类似的 Oracle 错误中也引用了此错误:
错误 18644587:ORACLEPARAMETERMETADATAPARSER GENERATES BAD STATEMENT FOR A UNION

目前尚不清楚该修复程序是否普遍可用。

于 2014-08-21T16:32:43.930 回答
1

也许为时已晚,但解决方法是在 LIKE 之前使用双引号限定字段,如下所示:

SELECT * FROM natperson WHERE "NAME" LIKE ?
于 2015-08-17T08:21:19.420 回答