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从今天开始，我的登录控制器（使用 Sentry）不再工作了。我已经将它更改了 10203902 次，但它一直给我错误：“需要 [登录] 属性”。在过去的 2-3 周内，此控制器运行良好。

登录控制器

 <?php namespace Digitus\Auth\Controllers;

use Illuminate\View\Environment as View;
use Cartalyst\Sentry\Sentry;
use Illuminate\Support\Facades\Input;
use Illuminate\Routing\Redirector as Redirect;

class LoginController extends \Digitus\Base\Controllers\BController{

    public function __construct(Input $input, View $view, Sentry $sentry, Redirect $redirect){
        $this->input    = $input;
        $this->view     = $view;
        $this->sentry   = $sentry;
        $this->user     = $this->sentry->getUser();
        $this->redirect = $redirect;

        if($this->sentry->check()) {
            $user = $this->sentry->getUser();
        } else {
            $user = null;
        }
        $this->view->share('loggedUser', $user);
    }

    protected $input;
    protected $view;
    protected $sentry;
    protected $redirect;

    public function index()
    {
        return $this->view->make('user.login');
    }

    public function login()
    {
        $user = $this->user->where('username', $this->input->get('email_or_username'))->orWhere('email', $this->input->get('email_or_username'))->first();
        $credentials = array(
            'email' => Input::get('email_or_username') ?: null,
            'password' => $this->input->get('password'),
        );
        try {
            $user = $this->sentry->authenticate($credentials, false);

            if($this->sentry->check())
            {
                return $this->redirect->to('admin');
            } else {
                return $this->redirect->to('');
            }
        }
        catch (\Exception $e)
        {
            return $this->redirect->to('login')->withErrors(array('login'=> $e->getMessage()));
        }
    }

}

看法

@extends('layouts.main')

@section('content')

<div class="col-md-4 col-md-offset-4">
    <div class="panel panel-info">
        <div class="panel-heading">PLease Login</div>
        <div class="panel-body">
            {{ Form::open(array('url' => 'login')) }}
            @if($errors->has('login'))
                <div class="alert alert-danger">
                    <a href="#" class="close" data-dismiss="alert">&times;</a>
                    {{ $errors->first('login', ':message') }}
                </div>
            @endif
            <div class="form-group">
                {{ Form::label('email_or_username', 'Email Address or Username') }}
                {{ Form::email('email_or_username', '', array('class'=>'form-control','placeholder'=>'Please enter your Email Address or Username to login', 'autofocus')) }}
            </div>
            <div class="form-group">
                {{ Form::label('password', 'Password') }}
                {{ Form::password('password', array('class'=>'form-control', 'placeholder'=>'Password')) }}
            </div>
            <div class="form-group">
                {{ Form::submit('Login', array('class'=>'btn btn-success')) }}
                {{ HTML::link('/', 'Cancel', array('class'=>'btn btn-danger')) }}
            </div>
            <hr>
            <div class="form-group">
                <h2>Don't have an account?</h2>
                {{ HTML::link('register', 'Please register here', array('class'=>'btn btn-primary btn-xs'))}}
            </div>
            {{ Form::close() }}
        </div>
    </div>
</div>

@stop

我已经问过很多人的解决方案或修复等。他们都没有工作..

PS & FYI：我还发布了 Sentry 配置，并且 login_attribute 是电子邮件。任何帮助或输入都会很棒。提前致谢..

4

1 回答 1

1

Sentry 还使用

protected static $loginAttribute = 'email';

要获取登录数据，请检查您是否对其进行了更改。这些是让你很难过的台词：

$loginName = $this->userProvider->getEmptyUser()->getLoginName();

$loginCredentialKey = (isset($credentials[$loginName])) ? $loginName : 'login';

基本上，如果$loginAttribute不可用，它将使用“登录”作为凭证密钥。所以你也可以测试给它想要的东西：

$credentials = array(
    'email' => Input::get('email_or_username') ?: null,
    'login' => Input::get('email_or_username') ?: null,
    'password' => $this->input->get('password'),
);

不幸的是，你不能有两个不同的字段来登录你的用户，所以如果你需要这个，你必须手动进行检查，所以你可能可以执行以下操作：

public function login()
{
    $user = $this->sentry->getUserProvider()->getEmptyUser();

    $user = $user->where('email', $this->input->get('email_or_username'))
                        ->orWhere('username', $this->input->get('email_or_username'))
                        ->first();

    try 
    {
        if ($user && Hash::check($this->input->get('password'), $user->password)) /// here you check if a user was found
        {
            $this->sentry->login($user, false); /// remember = false /// here is the login happening in case of true
        }
        else
        {
            // user not found or wrong password
        }
    }
    catch (\Exception $e)
    {
        return $this->redirect->to('login')->withErrors(array('login'=> $e->getMessage()));
    }
}
于 2014-03-24T16:21:51.570 回答