spring - 具有 Spring Security 和 Java Config 的自定义身份验证提供程序

Question

如何使用 Spring Security 和 Java 配置来定义自定义身份验证提供程序？我想在我自己的数据库上执行登录检查凭据。

Answer 1

以下是您需要的（CustomAuthenticationProvider是您需要由 Spring 管理的实现）

@Configuration
@EnableWebMvcSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private CustomAuthenticationProvider customAuthenticationProvider;

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        /**
         * Do your stuff here
         */
    }

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.authenticationProvider(customAuthenticationProvider);
    }
}

Answer 2

如baeldung.com所示，定义您的身份验证提供程序如下：

@Component
public class CustomAuthenticationProvider implements AuthenticationProvider {

    @Override
    public Authentication authenticate(Authentication authentication) 
      throws AuthenticationException {

        String name = authentication.getName();
        String password = authentication.getCredentials().toString();

        if (shouldAuthenticateAgainstThirdPartySystem(username, password)) {

            // use the credentials
            // and authenticate against the third-party system
            return new UsernamePasswordAuthenticationToken(
              name, password, new ArrayList<>());
        } else {
            return null;
        }
    }

    @Override
    public boolean supports(Class<?> authentication) {
        return authentication.equals(
          UsernamePasswordAuthenticationToken.class);
    }
}

以下代码是对应的java配置：

@Configuration
@EnableWebSecurity
@ComponentScan("org.project.security")
public class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private CustomAuthenticationProvider authProvider;

    @Override
    protected void configure(
      AuthenticationManagerBuilder auth) throws Exception {

        auth.authenticationProvider(authProvider);
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeRequests().anyRequest().authenticated()
            .and()
            .httpBasic();
    }
}