1

我正在尝试获取 URL“/videoGame”来运行“listAllVideoGames”方法和“/videoGame/#”(其中 # 是一个数字)来运行“getVideoGame”方法。使用“@priority”注释更改优先级我可以同时调用两个 URL,但找不到执行我描述的方法。

/**
 * @uri /videoGame
 * @uri /videoGame/:id
 */
class VideoGame extends Resource{

    protected function getDao(){
        return new VideoGameDao();
    }

    /**
     * @uri /videoGame
     * @json
     * @provides application/json
     * @method GET
     */
    public function listAllVideoGames(){
        return new Response(Response::OK,$this->dao->getAllVideoGames());
    }

    /**
     * @uri /videoGame/:id
     * @json
     * @provides application/json
     * @method GET
     */
    public function getVideoGame($id){
        $vg = $this->dao->getVideoGame($id);
        if ($vg){
            return new Response(Response::OK,$vg);
        }else{
            throw new NotFoundException();
        }
    }
}
4

1 回答 1

1

我发现这样做的唯一方法是为 GET 调用创建一种调度程序,如下所示:

/**
 * @uri /videoGame
 * @uri /videoGame/:id
 */
class VideoGame extends Resource{

    protected function getDao(){
        return new VideoGameDao();
    }

    /**
     * @uri /videoGame/:id
     * @provides application/json
     * @method GET
     */
    public function getVideoGames($id = 0){
        if (is_numeric($id) && $id > 0){
            return $this->getVideoGame($id);
        }else{
            return $this->getAllVideoGames();
        }
    }

    private function getVideoGame($id){
        $vg = $this->dao->getVideoGame($id);
        if ($vg){
            return new Response(Response::OK,$vg);
        }else{
            throw new NotFoundException();
        }
    }

    public function getAllVideoGames(){
        return new Response(Response::OK,$this->dao->getAllVideoGames());
    }
于 2014-03-25T04:24:24.320 回答