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我在 Commodore 64 中初始化了一块“.”板。

我想将单词随机放入板上，单词的每个字母都是“。” 在棋盘上（就像一个单词搜索游戏）。如果单词不适合，则可以放置下一个单词。我想将单词垂直和水平放置。这是我到目前为止所拥有的：（这使得点板为 10x10）

关于分离一个单词（我有硬编码的单词）并将它们垂直和水平放置在屏幕上的任何想法？

1060 rem: Subroutine Fill 
1070 rem: Purpose: read and data construct which fills b3$(x,x) with
1080 rem: either "."s or other random words depending on whether or not
1090 rem: the subroutine has been run before.
1100 x = 10
1110 rem: x represents the dimension for the board; in this case, 10
1120 rem: took out dim b3$(x, x)
1130 rem: array b3 = board = specifications for width and height (10)
1140 rem: i to x allows the horizontal aspect of board to be filled with "."s
1150 for i = 0 to x 
1160 rem: j to x allows the vertical aspect of board to be filled with "."s
1170 for j = 0 to x
1180 rem: board filled with dots horizontally and vertically
1190 b3$(i, j) = "."
1200 rem: end of first nested for loop
1210 next
1220 rem: end of second nested for loop
1230 next
1240 return

1400 dim wo$(9)
1410 wo$(0) = "word"
1420 wo$(1) = "stack"
1430 wo$(2) = "overflow"
1440 wo$(3) = "hello"
1450 wo$(4) = "no"
1460 wo$(5) = "how"
1470 wo$(6) = "why"
1480 wo$(7) = "start"
1490 wo$(8) = "end"
1500 wo$(9) = "done"
1510 print wo$(7)
1520 return

10 print "START"
20 rem: go to line 1100 in order to fill board with "."s because this is
30 rem: the board's initialization
40 gosub 1100
50 rem: looping from i to x allows for horizontal aspect of board to be printed
60 rem: x represents the width dimension of board, in this case, 10
70 for i = 0 to x
80 rem: looping from j to x allows for vertical aspect of board to be printed
90 rem: x represents the height dimension of board, in this case, 10
100 for j = 0 to x
110 rem: board initialized with "."s is printed
120 print b3$(i,j), 
130 rem: end of first for loop, looping from i to x put on 130; , USED 4 TAB
140 next
150 print
160 rem: end of second for loop, looping from j to x
170 next
180 rem: checks what at the random number is equal to; places word vertically
190 rem: if rand is 0 and places the word horizontally if rand is 1

现在我需要将单词放在网格中

有任何想法吗？

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1 回答 1

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字符串MID$函数

另一个重要的功能是MID$。此函数选择为其参数给出的任何字符串的一部分。

键入命令：

PRINT MID$("ABCOEFG",2,4)

结果向您展示了如何MID$工作。在这种情况下，它显示一个 4 个字符的字符串，从“ABCDEFG”的第二个字符开始。

在正式术语中，MID$ 函数采用三个参数，它们用逗号分隔并括在括号中。论据如下：

  • 第一个是要使用的字符串。
  • 第二个是一个数字，指定结果中第一个字符的位置。
  • 第三个是给出结果长度的另一个数字。

如您所料，任何参数都可以是适当类型的变量。结果的长度可以是从0（称为null字符串）到第一个参数的完整长度的任何内容。在实践中，它通常是一个字符。

这是一个输入单词并向后显示的简单程序。仔细研究它并注意函数LEN和MID$是如何使用的： 

10 INPUT "PLEASE TYPE A WORD"; X$  
20 PRINT "YOUR WORD BACKWARD IS"  
30 FOR J = LEN(X$) TO 1 STEP - 1  
40 PRINT MID$(X$,J, 1);  
50 NEXT J  
60 STOP

键入程序并自己检查；尝试 1、2 或更多字符的单词。

于 2014-03-24T07:10:49.697 回答