0

目前我正在尝试在我的新项目中插入很多值，但我无法弄清楚如何准确地做到这一点。我的“最简单”的 SQL 查询如下，这个函数的工作方式应该是这样的：

dbClient.setQuery("INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`,     `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES " +
"('private', 'VIP CADEAU: Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 0, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');");
dbClient.addParameter("username", Session.GetHabbo().Username);
dbClient.runQuery();

但现在我想插入超过 1 个值，使用以下查询：

INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`, `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),

在此之后还有成千上万的其他行......

但我完全不知道如何运行调整我的代码 ( dbClient) 以使其工作......一个合乎逻辑但混乱的解决方案可能是：

dbClient.setQuery("INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`,     `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES " +
    "('private', 'VIP CADEAU: Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 0, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');");
dbClient.setQuery("INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`,     `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES " +
    "('private', 'VIP CADEAU: Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 0, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');");

但我不想在我的代码中重复“插入”超过 1000 次。

4

2 回答 2

1

选项：

  • 循环，多次使用不同参数的简单代码
  • 使用可以为您做到这一点的工具（dapper 有一些接近基本的技巧，大多数 ORM 将允许简单的基于列表的插入）
  • 对于非常大的插入，“批量复制”如果您的提供商支持它 - 也许使用 FastMember 将列表转换为IDataReader
于 2014-03-23T13:21:08.770 回答
1

您只需要多个INSERT语句：

INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`, `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');

INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`, `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');
于 2014-03-23T13:22:51.393 回答