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我需要让用户输入一个高度值,如果它高于 23 或小于 0,它应该再次询问。然后它应该打印一个金字塔,有点像马里奥兄弟游戏结束时的楼梯(右侧有 2 个标签,参见示例)。问题是代码运行并且不打印任何#,代码刚刚结束。这是一个在线课程,所以请不要只发布代码,如果您要发布完整的代码,请解释它。

金字塔示例:https ://www.dropbox.com/s/4fyg2ls0eml7asi/Screenshot%20from%202014-03-20%2002%3A15%3A08.png

我遵循的流程图:http: //i.imgur.com/otuDOtK.png

#include <stdio.h>
//#include "cs50.h"

int main(void){
    //int h = 0;
    printf("Enter height between 0 and 23: ");
    int h = scanf("%d", &h);
    while (h < 0 || h > 23){
        printf("Retry: ");
        h = scanf("%d", &h);
    }
    int l = 1;
    if (h == 0){
        //printf("ln21\n"); //Debug
        return;
    }
    int s = h - 1;
    int b = l + 1;
    if (s == 0){
        if (b == 0){
            printf("\n");
    h = h - 1;
    l = l + 1;
    if (h == 0){
        return;
    }
        }
    }
    else{
    printf("#");
    b = b - 1;
    }
}
4

1 回答 1

0
#include <stdio.h>

int main(){
    int height = 8;//Number of repetitions of basic.
    int max_width = height + 1;//Number of block(#) in the largest display
    int i, j, w;
    for(i = 0; i < height; ++i){
        printf("%*s", max_width -(i+2), "");//Print a space in front of the block
        for(w = 0; w < i+2; ++w){
            printf("#");//display a block of each floor
        }
        printf("\n");
    }
    printf("\n");
    return 0;
}

#include <stdio.h>
#include <string.h>

int main(){
    int height = 8;
    int max_width = height + 1;
    char wall[max_width + 1];
    int i;
    memset(wall, '#', sizeof(wall)-1);// make a block of maximum.
    wall[sizeof(wall)-1] = '\0';
    for(i = 0; i < height; ++i){
        printf("%*.*s\n", max_width, i+2, wall);//View of block size and the required blank
    }
    return 0;
}
于 2014-03-20T04:02:01.387 回答