2

这是马鹿的一张扫描图。我注意到当我上传图片（用户可以上传）之前我遇到了崩溃Launching module crlf。因此，只需使用我网站的一个新实例，我就运行了它并得到了下面的结果。

我的问题是 1. 我如何修复崩溃 2. 我如何找出导致崩溃的原因。我使用 -v 2 找出 url 并将它们记录到我的应用程序中。在这两种情况下，我都没有看到任何问题，并且项目在我的代码之外崩溃 3. 我如何解决下面的 unicode 警告？

 Wapiti-2.2.1 (wapiti.sourceforge.net)
..............................
 Notice
========
This scan has been saved in the file C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src/s
cans/localhost:17357.xml
You can use it to perform attacks without scanning again the web site with the "
-k" parameter
[*] Loading modules :
        mod_crlf, mod_exec, mod_file, mod_sql, mod_xss, mod_backup, mod_htaccess
, mod_blindsql, mod_permanentxss, mod_nikto

[+] Launching module crlf

[+] Launching module exec

[+] Launching module file

[+] Launching module sql
C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\mod_sql.py:185: UnicodeWarning:
 Unicode equal comparison failed to convert both arguments to Unicode - interpre
ting them as being unequal
  if (page, tmp) not in self.attackedPOST:

[+] Launching module xss
Traceback (most recent call last):
  File "wapiti.py", line 449, in <module>
    wap.attack()
  File "wapiti.py", line 266, in attack
    x.attack(self.urls, self.forms)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\attack.py", line 121, i
n attack
    self.attackGET(page, dictio, headers)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\mod_xss.py", line 71, i
n attackGET
    self.findXSS(page, {}, "", code, "", payloads, headers["link_encoding"])
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\mod_xss.py", line 306,
in findXSS
    dat = self.HTTP.send(url).getPage()
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\HTTP.py", line 94, in send

    info, data = self.h.request(target, headers = _headers)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\httplib2\__init__.py", lin
e 1084, in request
    (response, content) = self._request(conn, authority, uri, request_uri, metho
d, body, headers, redirections, cachekey)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\httplib2\__init__.py", lin
e 888, in _request
    (response, content) = self._conn_request(conn, request_uri, method, body, he
aders)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\httplib2\__init__.py", lin
e 853, in _conn_request
    response = conn.getresponse()
  File "C:\dev\bin\Python26\lib\httplib.py", line 974, in getresponse
    response.begin()
  File "C:\dev\bin\Python26\lib\httplib.py", line 391, in begin
    version, status, reason = self._read_status()
  File "C:\dev\bin\Python26\lib\httplib.py", line 349, in _read_status
    line = self.fp.readline()
  File "C:\dev\bin\Python26\lib\socket.py", line 397, in readline
    data = recv(1)
socket.error: [Errno 10054] An existing connection was forcibly closed by the re
mote host
4

1 回答 1

2

Wapiti 可能会导致应用程序崩溃，因为它使用了大量的应用程序。进行 XSS 测试时跟踪的 Wapiti 堆栈，我认为 xss 测试不会使应用程序崩溃。但是，通过提交大量 1 类型的请求，这可能会导致 DoS 条件。您需要追踪 Wapiti 发出的最后一个请求。Wapiti 有一个详细模式，我认为它的 -v 会打印出它发出的每个请求。一旦您拥有崩溃的文件，您应该手动查看它。

Wapiti 的盲目 sql 注入攻击模块使用 mysql 的 benchmark() 函数，它会DoS你的 mysql 服务器，如果你在扫描整个站点时遇到问题，我建议关闭这个。

于 2010-02-12T20:17:51.843 回答