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如何从下面的查询中以更有效和优雅的方式获取 MY_LATEST_INSERTED_NUMBER_BASING_ON_MY_DATE_COLUMN_FOR_ID_CONTEXT ?

SELECT MAX(MY_DATE_COLUMN),
 ID,
 listagg(SOME_COLUMN, '') within GROUP (ORDER BY MY_DATE_COLUMN),
 SUBSTR(
      listagg(MY_NUMBER, ';') within GROUP (ORDER BY MY_DATE_COLUMN DESC),
      1,
      instr(
             listagg(MY_NUMBER, ';') within GROUP (ORDER BY MY_DATE_COLUMN DESC),'-') - 1
           ) as MY_LATEST_INSERTED_NUMBER_BASING_ON_MY_DATE_COLUMN_IN_ID_CONTEXT
 FROM MY_TABLE
 GROUP BY ID;
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1 回答 1

1

如果我理解正确,你想要keep

SELECT MAX(MY_DATE_COLUMN), ID,
       listagg(SOME_COLUMN, '') within GROUP (ORDER BY MY_DATE_COLUMN),
       max(MY_LATEST_INSERTED_NUMBER_BASING_ON_MY_DATE_COLUMN_IN_ID_CONTEXT)
           keep (dense_rank first order by MY_DATE_COLUMN DESC)
FROM MY_TABLE
GROUP BY ID;

ALL CAPS 并不能真正帮助传达您想要做的事情。

于 2014-03-14T12:33:47.720 回答