python - 如何组合多个defaultdict(Counter)？

Question

如何组合多个defaultdict(Counter)？

鉴于我有两个defaultdict(Counter)，我尝试了以下方法，它有效，但还有其他方法可以实现组合吗？

>>> from collections import Counter, defaultdict
>>> x = {'a':Counter(['abc','def','abc']), 'b':Counter(['ghi', 'jkl'])}
>>> y = {'a':Counter(['abc','def','mno']), 'c':Counter(['lmn', 'jkl'])}
>>> z = x+y
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for +: 'dict' and 'dict'
>>> z = defaultdict(Counter)
>>> for i in x:
...     z[i].update(x[i])
... 
>>> for i in y:
...     z[i].update(y[i])
... 
>>> z
defaultdict(<class 'collections.Counter'>, {'a': Counter({'abc': 3, 'def': 2, 'mno': 1}), 'c': Counter({'jkl': 1, 'lmn': 1}), 'b': Counter({'jkl': 1, 'ghi': 1})})

Answer 1

这似乎没问题，如果有点代码高尔夫：

{k:(x.get(k,Counter()) + y.get(k,Counter())) for k in (x.keys()+y.keys())}
Out[23]: 
{'a': Counter({'abc': 3, 'def': 2, 'mno': 1}),
 'b': Counter({'jkl': 1, 'ghi': 1}),
 'c': Counter({'jkl': 1, 'lmn': 1})}

如果你想坚持defaultdict输出，你可以将事情简化为一个循环itertools.chain：

z = defaultdict(Counter)

for k,v in chain(x.iteritems(), y.iteritems()):
    z[k].update(v)