c++ - Accessing data members shadowed by parameters

Question

In Java you can access variables in a class by using the keyword this, so you don't have to figure out a new name for the parameters in a function.

Java snippet:

private int x;

public int setX(int x) {
  this.x = x;
}

Is there something similar in C++? If not, what the best practice is for naming function parameters?

score 4 · Accepted Answer

4

如果你想通过访问成员this，它是一个指针，所以使用this->x.

于 2010-02-09T21:06:54.333 回答

score 1 · Accepted Answer

class Example {
    int x;
    /* ... */
public:
    void setX(int x) {
        this->x = x;
    }
};

哦，在构造函数初始化列表中，你不需要this->：

Example(int x) : x(x) { }

不过，我会认为这种边缘糟糕的风格。

score 0 · Accepted Answer

取决于编码约定。

来自 Google 的C++ 风格指南：

void set_some_var(int var) { some_var_ = var; }
int some_other_var_;

score 0 · Accepted Answer

private int x;

public int setX(int newX) {
  x = newX;
  return x;  //is this what you're trying to return?  
}

在大多数情况下，我会制作一个像这样的 void IE 的“设置”函数

public:
void setX(int newX) {
  x = newX;
}

4 回答 4