我对这个 MIPS 程序的评论是否准确地解释了每个语句行的作用?
.data
str1: .asciiz "Enter the first integer: "
str2: .asciiz "Enter the second integer: "
str3: .asciiz "The sum is "
newline: .asciiz "\n"
.text # instructions follow this line
main: # indicates start of code (first instruction to execute)
addi $v0, $zero, 4
# adds zero and imm value 4 and stores in 32-bit function result registers
la $a0, str1
#load system register $a0, with the address of the string to be output
syscall
addi $v0, $zero, 5
# adds zero and imm value 5 and stores in 32-bit function result registers
syscall
add $s0, $zero, $v0
#adds 0 and value in $v0 and stores in $s0
addi $v0, $zero, 4
# adds zero and imm value 4 and stores in 32-bit function result registers
la $a0, str2
#load system register $a0, with the address of the string to be output
syscall
addi $v0, $zero, 5
# adds zero and imm value 5 and stores in 32-bit function result registers
syscall
add $s1, $zero, $v0
#adds 0 and value in $v0 and stores in $s1
add $s2, $s0, $s1
# adds value in $s0 and value in $s1 and stores in $s2
addi $v0, $zero, 4
# adds zero and imm value 4 and stores in 32-bit function result registers
la $a0, str3
# load system register $a0, with the address of the string to be output
syscall
addi $v0, $zero, 1
# adds zero and imm value 1 and stores in 32-bit function result registers
add $a0, $zero, $s2
# adds value in $s2 and 0 and stores in system register $a0
syscall
addi $v0, $zero, 4
# adds zero and imm value 4 and stores in 32-bit function result registers
la $a0, newline
# load system register $a0, with the address of the string to be output
syscall
addi $v0, $zero, 10
# adds zero and imm value 10 and stores in 32-bit function result registers
syscall
jr $ra
# jump to address contained in $ra
系统调用有什么作用,因为我在网上看到了不同的评论?另外,如果我想修改这个程序以打印第一个整数第二个整数的时间量,我该怎么做?例如:1st: 2, 2nd: 5,所以我打印 2 5 次。