70

我在实现双击时遇到问题。好吧，我实现了onGestureListener并且我拥有了gestureDetector，但我不确定问题出在哪里，这是我的代码：

 public class home extends TabActivity implements OnGestureListener {
    /** Called when the activity is first created. */

 private EditText queryText;
 private ResultsAdapter m_adapter;
 private ProgressDialog pd;
 final Handler h = new Handler();
 private TabHost mTabHost;
 private ArrayList<SearchItem> sResultsArr = new ArrayList<SearchItem>();
 private String queryStr;
 private JSONObject searchResponse;
 private GestureDetector gestureScanner;

 final Runnable mUpdateResults = new Runnable() {
        public void run() {
         updateListUi();
        }
    };

 @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        Button search = (Button)findViewById(R.id.search);
        Button testButt = (Button)findViewById(R.id.testbutt);
        queryText = (EditText)findViewById(R.id.query);
        ListView lvr = (ListView)findViewById(R.id.search_results);

      //initialise the arrayAdapter
        this.m_adapter = new ResultsAdapter(home.this, R.layout.listrow, sResultsArr);
        lvr.setAdapter(this.m_adapter);
        lvr.setOnItemClickListener(new OnItemClickListener(){
   @Override
   public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
     long arg3) {
    // TODO Auto-generated method stub
         pd = ProgressDialog.show(home.this, null,"Loading products from server", true, false);

   }

        });
        gestureScanner = new GestureDetector(this,this);
        gestureScanner.setOnDoubleTapListener(new OnDoubleTapListener(){ 
            public boolean onDoubleTap(MotionEvent e) { 
                 //viewA.setText("-" + "onDoubleTap" + "-"); 
         pd = ProgressDialog.show(home.this, null,"Loading products from server", true, false);

                 return false; 
            } 
            public boolean onDoubleTapEvent(MotionEvent e) { 
                // viewA.setText("-" + "onDoubleTapEvent" + "-"); 
                 return false; 
            } 
            public boolean onSingleTapConfirmed(MotionEvent e) { 
                 //viewA.setText("-" + "onSingleTapConfirmed" + "-"); 
                 return false; 
            } 

     });


        //initialise tab contents
        mTabHost = getTabHost();
        mTabHost.addTab(mTabHost.newTabSpec("tab1").setIndicator("Home").setContent(R.id.homepage));
        mTabHost.addTab(mTabHost.newTabSpec("tab2").setIndicator("Search Results").setContent(R.id.tab2));
        mTabHost.setCurrentTab(0);

        //sets the respective listeners
        testButt.setOnClickListener(new View.OnClickListener() {
        public void onClick(View arg0) {

         if(mTabHost.getTabWidget().getVisibility()==View.GONE){
          mTabHost.getTabWidget().setVisibility(View.VISIBLE);
         }
         else{
          mTabHost.getTabWidget().setVisibility(View.GONE);
         }
        }
     });

        search.setOnClickListener(new View.OnClickListener() {
        public void onClick(View arg0) {
         sResultsArr.clear();
         queryStr = "http://rose.mosuma.com/mobile?query=" + queryText.getText().toString();
         pd = ProgressDialog.show(home.this, null,"Loading products from server", true, false);
         goSearch();
      }
     });
    }

 //updates the listUI whenever after receiving the response from the server
 public void updateListUi(){  
    if(sResultsArr.size() > 0){

       }

    try{
     String ptypename;
     int count;
     LinearLayout ptypebar = (LinearLayout)findViewById(R.id.productCat);
     ptypebar.removeAllViews();
     JSONArray ptypes = searchResponse.getJSONArray("ptypes"); 
     for(int index =0;index < ptypes.length();index++){
      JSONObject ptype = ptypes.getJSONObject(index);
      count = ptype.getInt("count");      
      ptypename = ptype.getString("ptypename"); 

      //add into tab 2's UI

      //ImageView icon = new ImageView(this);
      TextView t = new TextView(home.this);
      t.setText(ptypename + " (" + count + ")");
      ptypebar.addView(t);
     }
    }
    catch(JSONException e){

    }
   //if(m_adapter.getItems() != sResultsArr){
    ArrayList<SearchItem> a  = m_adapter.getItems(); 
    a = sResultsArr;
   //}
      m_adapter.notifyDataSetChanged();
     pd.dismiss();
 }

 public void goSearch(){
  mTabHost.setCurrentTab(1);

  //separate thread for making http request and updating the arraylist
  Thread t = new Thread() {
           public void run() {

            searchResponse = sendSearchQuery(queryStr);
            try{
             JSONArray results = searchResponse.getJSONArray("results");

             //this is stupid. i probably have to see how to make a json adapter
             for(int index =0;index < results.length();index++){

              JSONObject product = results.getJSONObject(index);

              //gets the searched products from the json object
              URL imgUrl =  new URL(product.getString("image"));
              String productname = product.getString("productname");
              String ptypename = product.getString("ptypename");
              int pid = product.getInt("pid");
              int positive = product.getInt("pos");
              int negative = product.getInt("neg");
              int neutral = product.getInt("neu");


              SearchItem item  = new SearchItem(imgUrl,productname,ptypename,neutral,positive,negative,pid);
              sResultsArr.add(item);
             }
            }
            catch(JSONException e){

            }
            catch(Exception e){

               }
            //returns back to UI therad
            h.post(mUpdateResults);
           }
       };
       t.start();
 }

 //sends a request with qry as URL
 //and receives back a JSONobject as response
 public JSONObject sendSearchQuery(String qry){
  HttpRequest r = new HttpRequest();
  JSONObject response = r.sendHttpRequest(qry);  
  return response;
 }

 @Override
 public boolean onDown(MotionEvent arg0) {
      return gestureScanner.onTouchEvent(arg0); 
 }

 @Override
 public boolean onFling(MotionEvent arg0, MotionEvent arg1, float arg2,
   float arg3) {
  // TODO Auto-generated method stub
  return false;
 }

 @Override
 public void onLongPress(MotionEvent arg0) {
  // TODO Auto-generated method stub

 }

 @Override
 public boolean onScroll(MotionEvent arg0, MotionEvent arg1, float arg2,
   float arg3) {
  // TODO Auto-generated method stub
  return false;
 }

 @Override
 public void onShowPress(MotionEvent arg0) {
  // TODO Auto-generated method stub

 }

 @Override
 public boolean onSingleTapUp(MotionEvent arg0) {
  // TODO Auto-generated method stub
  return false;
 }

哦，另一个问题，如果我ListView有一个onItemClickListener，android可以在单击或双击之间检测它吗？

4

25 回答 25

115

您可以使用 GestureDetector。请参阅以下代码：

public class MyView extends View {

    GestureDetector gestureDetector;

    public MyView(Context context, AttributeSet attrs) {
        super(context, attrs);
                // creating new gesture detector
        gestureDetector = new GestureDetector(context, new GestureListener());
    }

    // skipping measure calculation and drawing

        // delegate the event to the gesture detector
    @Override
    public boolean onTouchEvent(MotionEvent e) {
        return gestureDetector.onTouchEvent(e);
    }


    private class GestureListener extends GestureDetector.SimpleOnGestureListener {

        @Override
        public boolean onDown(MotionEvent e) {
            return true;
        }
        // event when double tap occurs
        @Override
        public boolean onDoubleTap(MotionEvent e) {
            float x = e.getX();
            float y = e.getY();

            Log.d("Double Tap", "Tapped at: (" + x + "," + y + ")");

            return true;
        }
    }
}

您可以覆盖侦听器的其他方法以获取单击、弹跳等。

于 2011-06-09T08:28:12.330 回答
73

作为 GestureDetector 的轻量级替代品，您可以使用此类

public abstract class DoubleClickListener implements OnClickListener {

    private static final long DOUBLE_CLICK_TIME_DELTA = 300;//milliseconds

    long lastClickTime = 0;

    @Override
    public void onClick(View v) {
        long clickTime = System.currentTimeMillis();
        if (clickTime - lastClickTime < DOUBLE_CLICK_TIME_DELTA){
            onDoubleClick(v);
        } else {
            onSingleClick(v);
        }
        lastClickTime = clickTime;
    }

    public abstract void onSingleClick(View v);
    public abstract void onDoubleClick(View v);
}

例子：

    view.setOnClickListener(new DoubleClickListener() {

        @Override
        public void onSingleClick(View v) {

        }

        @Override
        public void onDoubleClick(View v) {

        }
    });
于 2014-02-13T20:08:44.550 回答
23

为什么不用长按？还是您已经将其用于其他用途？长按相对于双击的优势：

  • 长按是 UI 指南中推荐的交互，双击不是。
  • 这是用户的期望；用户可能找不到 Double Touch 操作，因为他们不会去寻找它
  • 它已经在 API 中处理。
  • 实现双点触控会影响单点触控的处理，因为您必须等待查看每个单点触控是否会变成双点触控，然后才能处理它。
于 2010-02-07T21:19:19.773 回答
16

将“Bu​​ghi”“DoubleClickListner”和“Jayant Arora”定时器组合在一个包含的类中：

public abstract class DoubleClickListener implements OnClickListener {

    private Timer timer = null;  //at class level;
    private int DELAY   = 400;

    private static final long DOUBLE_CLICK_TIME_DELTA = 300;//milliseconds

    long lastClickTime = 0;

    @Override
    public void onClick(View v) {
        long clickTime = System.currentTimeMillis();
        if (clickTime - lastClickTime < DOUBLE_CLICK_TIME_DELTA){
            processDoubleClickEvent(v);
        } else {
            processSingleClickEvent(v);
        }
        lastClickTime = clickTime;
    }



    public void processSingleClickEvent(final View v){

        final Handler handler=new Handler();
        final Runnable mRunnable=new Runnable(){
            public void run(){
                onSingleClick(v); //Do what ever u want on single click

            }
        };

        TimerTask timertask=new TimerTask(){
            @Override
            public void run(){
                handler.post(mRunnable);
            }
        };
        timer=new Timer();
        timer.schedule(timertask,DELAY);

    }

    public void processDoubleClickEvent(View v){
        if(timer!=null)
        {
            timer.cancel(); //Cancels Running Tasks or Waiting Tasks.
            timer.purge();  //Frees Memory by erasing cancelled Tasks.
        }
        onDoubleClick(v);//Do what ever u want on Double Click
    }

    public abstract void onSingleClick(View v);

    public abstract void onDoubleClick(View v);
}

并且可以称为：

view.setOnClickListener(new DoubleClickListener() {

            @Override
            public void onSingleClick(View v) {

            }

            @Override
            public void onDoubleClick(View v) {

            }
        });
于 2016-11-15T18:22:54.867 回答
8

如果您不想使用自定义视图，则可以使用以下方法。例如图像视图

// class level

GestureDetector gestureDetector;
boolean tapped;
ImageView imageView;

// inside onCreate of Activity or Fragment
gestureDetector = new GestureDetector(context,new GestureListener());

//------------------------------------------------ --------------------------------

public class GestureListener extends
        GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {

        return true;
    }

    // event when double tap occurs
    @Override
    public boolean onDoubleTap(MotionEvent e) {

        tapped = !tapped;

        if (tapped) {



        } else {



        }

        return true;
    }
}

//------------------------------------------------ --------------------------------

对于图像视图

imageView.setOnTouchListener(new OnTouchListener() {

        @Override
        public boolean onTouch(View v, MotionEvent event) {
            // TODO Auto-generated method stub
            return gestureDetector.onTouchEvent(event);
        }

    });
于 2013-04-26T09:13:52.423 回答
4

这是我的解决方案，它使用 default setOnItemClickListener()。我有同样的任务要执行。很快我将在我的 github 上发布示例和自定义类。给出简要说明。我不确定以毫秒为单位的时间是否是系统（参见ViewConfiguration.getDoubleTapTimeout()源代码）在单击和双击之间决定的正确差异。

编辑： 在此处查看： https ://github.com/NikolaDespotoski/DoubleTapListView或 https://github.com/NikolaDespotoski/DoubleTapListViewHandler

于 2012-01-06T22:27:27.070 回答
4

GuestureDetecter 在大多数设备上运行良好，我想知道如何在双击事件上自定义两次单击之间的时间，我无法做到这一点。我通过“Bughi”“DoubleClickListner”更新了上面的代码，添加了一个使用处理程序的计时器，该处理程序在单击特定延迟后执行代码，如果在该延迟之前执行双击，它将取消计时器和单击任务并且只执行双击任务。代码运行良好使其非常适合用作双击列表器：

  private Timer timer = null;  //at class level;
  private int DELAY   = 500;

  view.setOnClickListener(new DoubleClickListener() {

        @Override
        public void onSingleClick(View v) {

    final Handler  handler          = new Handler();
                final Runnable mRunnable        = new Runnable() {
                    public void run() {
                        processSingleClickEvent(v); //Do what ever u want on single click

                    }
                };

                TimerTask timertask = new TimerTask() {
                    @Override
                    public void run() {
                        handler.post(mRunnable);
                    }
                };
                timer   =   new Timer();
                timer.schedule(timertask, DELAY);       

        }

        @Override
        public void onDoubleClick(View v) {
                if(timer!=null)
                {
                 timer.cancel(); //Cancels Running Tasks or Waiting Tasks.
                 timer.purge();  //Frees Memory by erasing cancelled Tasks.
                }
              processDoubleClickEvent(v);//Do what ever u want on Double Click

        }
    });
于 2014-10-10T10:14:32.587 回答
3

双击和单击

仅双击

SimpleOnGestureListener通过使用（如Hannes Niederhausen 的回答所示）很容易检测到视图上的双击。

private class GestureListener extends GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onDoubleTap(MotionEvent e) {
        return true;
    }
}

我看不出重新发明这个逻辑的巨大优势（比如bughi 的回答）。

双击和单击有延迟

您还可以使用SimpleOnGestureListener来区分单击和双击作为互斥事件。为此，您只需覆盖onSingleTapConfirmed. 这将延迟运行单击代码，直到系统确定用户没有双击（即延迟 > ViewConfiguration.getDoubleTapTimeout()）。绝对没有理由为此重新发明所有逻辑（就像在this，this和其他答案中所做的那样）。

private class GestureListener extends GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onSingleTapConfirmed(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onDoubleTap(MotionEvent e) {
        return true;
    }
}

无延迟的双击和单击

潜在的问题onSingleTapConfirmed是延迟。有时明显的延迟是不可接受的。在这种情况下，您可以替换onSingleTapConfirmed为onSingleTapUp.

private class GestureListener extends GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onSingleTapUp(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onDoubleTap(MotionEvent e) {
        return true;
    }
}

但是，您需要意识到，如果双击，两者都会被调用。 （这基本上就是bughi 的回答以及一些评论者所抱怨的。）您要么需要使用延迟，要么同时调用这两种方法。不可能在没有延迟的情况下单击一次，同时知道用户是否要再次点击。onSingleTapUp onDoubleTap

如果您不能接受单击延迟，那么您有几个选择：

  • 两者都接受，onSingleTapUp然后onDoubleTap会被要求双击。只需适当地划分你的逻辑，这样就没有关系了。这基本上是我在自定义键盘上实现双击大写锁定时所做的。

  • 不要使用双击。对于大多数事情来说，这不是一个直观的 UI 操作。正如Dave Webb 建议的那样，长按可能更好。您还可以使用以下方法实现SimpleOnGestureListener：

    private class GestureListener extends GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onSingleTapUp(MotionEvent e) {
        return true;
    }

    @Override
    public void onLongPress(MotionEvent e) {

    }
}
于 2018-02-17T19:00:33.810 回答
3 
boolean nonDoubleClick = true, singleClick = false;
        private long firstClickTime = 0L;
        private final int DOUBLE_CLICK_TIMEOUT = 200;

        listview.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View v, int pos, long id) {
                // TODO Auto-generated method stub
                Handler handler = new Handler();
                handler.postDelayed(new Runnable() {

                    @Override
                    public void run() {
                        // TODO Auto-generated method stub
                        if (singleClick) {
                            Toast.makeText(getApplicationContext(), "Single Tap Detected", Toast.LENGTH_SHORT).show();
                        }
                        firstClickTime = 0L;
                        nonDoubleClick = true;
                        singleClick = false;
                    }
                }, 200);
                if (firstClickTime == 0) {
                    firstClickTime = SystemClock.elapsedRealtime();
                    nonDoubleClick = true;
                    singleClick = true;
                } else {
                    long deltaTime = SystemClock.elapsedRealtime() - firstClickTime;
                    firstClickTime = 0;
                    if (deltaTime < DOUBLE_CLICK_TIMEOUT) {
                        nonDoubleClick = false;
                        singleClick = false;
                        Toast.makeText(getApplicationContext(), "Double Tap Detected", Toast.LENGTH_SHORT).show();
                    }
                }

            }
        });
于 2015-10-27T15:21:20.260 回答
2

即兴的dhruvi代码

public abstract class DoubleClickListener implements View.OnClickListener {

private static final long DOUBLE_CLICK_TIME_DELTA = 300;//milliseconds

long lastClickTime = 0;
boolean tap = true;

@Override
public void onClick(View v) {
    long clickTime = System.currentTimeMillis();
    if (clickTime - lastClickTime < DOUBLE_CLICK_TIME_DELTA){
        onDoubleClick(v);
        tap = false;
    } else
        tap = true;

    v.postDelayed(new Runnable() {
        @Override
        public void run() {
            if(tap)
                onSingleClick();
        }
    },DOUBLE_CLICK_TIME_DELTA);

    lastClickTime = clickTime;
}

public abstract void onDoubleClick(View v);

public abstract void onSingleClick();
}
于 2018-01-03T21:05:47.900 回答
2

我的解决方案，可能会有所帮助。

long lastTouchUpTime = 0;
boolean isDoubleClick = false;

private void performDoubleClick() {
    long currentTime = System.currentTimeMillis();
    if(!isDoubleClick && currentTime - lastTouchUpTime < DOUBLE_CLICK_TIME_INTERVAL) {
        isDoubleClick = true;
        lastTouchUpTime = currentTime;
        Toast.makeText(context, "double click", Toast.LENGTH_SHORT).show();
    }
    else {
        lastTouchUpTime = currentTime;
        isDoubleClick = false;
    }
}
于 2015-09-02T08:19:10.350 回答
2

这是一个在执行任何操作之前等待是否有第二个 clic 的解决方案

  int init = 0;
  myView.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {


            if (init == 0) {
                init++;
                new Handler().postDelayed(new Runnable() {
                    @Override
                    public void run() {



                        if (init == 1) {
                            Log.d("hereGoes", "actionOne");
                        } else {
                            Log.d("hereGoes", "actionTwo");
                        }


                        init = 0;
                    }
                }, 250);
            } else {
                init++;
            }

        }
    });
于 2019-08-09T12:08:50.400 回答
2

如果您使用的是 Kotlin，那么您可以这样做：

我花了很多时间将此代码转换为 Kotlin 希望它可以节省某人的时间

创建手势检测器：

      val gestureDetector = GestureDetector(this, object : GestureDetector.SimpleOnGestureListener() {
            override fun onDoubleTap(e: MotionEvent): Boolean {

                Toast.makeText(this@DemoActivity,"Double Tap",Toast.LENGTH_LONG).show()

                //Show or hide Ip address on double tap
                toggleIPaddressVisibility()

                return true;
            }

            override fun onLongPress(e: MotionEvent) {
                super.onLongPress(e);

                //rotate frame on long press
                toggleFrameRotation()

                Toast.makeText(this@DemoActivity,"LongClick",Toast.LENGTH_LONG).show()
            }

            override fun onDoubleTapEvent(e: MotionEvent): Boolean {
                return true
            }

            override fun onDown(e: MotionEvent): Boolean {
                return true
            }
        })

分配给您的任何视图：

        IPAddress.setOnTouchListener { v, event ->
          return@setOnTouchListener  gestureDetector.onTouchEvent(event)
        }
于 2019-03-12T09:47:00.337 回答
1 
public class MyView extends View {

GestureDetector gestureDetector;

public MyView(Context context, AttributeSet attrs) {
    super(context, attrs);
            // creating new gesture detector
    gestureDetector = new GestureDetector(context, new GestureListener());
}

// skipping measure calculation and drawing

    // delegate the event to the gesture detector
@Override
public boolean onTouchEvent(MotionEvent e) {
    return gestureDetector.onTouchEvent(e);
}


private class GestureListener extends GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {
        return true;
    }
    // event when double tap occurs
    @Override
    public boolean onDoubleTap(MotionEvent e) {
        float x = e.getX();
        float y = e.getY();

        Log.d("Double Tap", "Tapped at: (" + x + "," + y + ")");

        return true;
    }
}
}
于 2016-06-09T12:38:59.977 回答
1

实现单击和双击

public abstract class DoubleClickListener implements View.OnClickListener {

private static final long DOUBLE_CLICK_TIME_DELTA = 200;

private long lastClickTime = 0;

private View view;

private Handler handler = new Handler();
private Runnable runnable = new Runnable() {
    @Override
    public void run() {
        onSingleClick(view);
    }
};

private void runTimer(){
    handler.removeCallbacks(runnable);
    handler.postDelayed(runnable,DOUBLE_CLICK_TIME_DELTA);
}

@Override
public void onClick(View view) {
    this.view = view;
    long clickTime = System.currentTimeMillis();
    if (clickTime - lastClickTime < DOUBLE_CLICK_TIME_DELTA){
        handler.removeCallbacks(runnable);
        lastClickTime = 0;
        onDoubleClick(view);
    } else {
        runTimer();
        lastClickTime = clickTime;
    }
}

public abstract void onSingleClick(View v);
public abstract void onDoubleClick(View v);

}

于 2016-02-24T13:45:55.567 回答
1

线程 + 接口 = DoubleTapListener、AnyTap 监听器等

在此示例中，我使用线程实现了 DoubleTap 侦听器。您可以像使用任何 ClickListener 一样将我的侦听器添加到任何 View 对象中。使用这种方法，您可以轻松地关闭任何类型的点击侦听器。

yourButton.setOnClickListener(new DoubleTapListener(this));

1）我的Listrener类 

public class DoubleTapListener  implements View.OnClickListener{

   private boolean isRunning= false;
   private int resetInTime =500;
   private int counter=0;
   private DoubleTapCallback listener;

   public DoubleTapListener(Context context){
       listener = (DoubleTapCallback)context;
       Log.d("Double Tap","New");
   }

   @Override
   public void onClick(View v) {

       if(isRunning){
          if(counter==1)
              listener.onDoubleClick(v);
       }

       counter++;

       if(!isRunning){
          isRunning=true;
          new Thread(new Runnable() {
             @Override
             public void run() {
                 try {
                    Thread.sleep(resetInTime);
                    isRunning = false;
                    counter=0;
                 } catch (InterruptedException e) {
                    e.printStackTrace();
                 }
             }
           }).start();
       }
   }
}

2) 监听回调

public interface DoubleTapCallback {

      public void onDoubleClick(View v);

}

3）在您的活动中实施

public class MainActivity extends AppCompatActivity implements DoubleTapCallback{

private Button button;
private int counter;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    button   = (Button)findViewById(R.id.button);      
    button.setOnClickListener(new DoubleTapListener(this));  // Set mt listener

}

@Override
public void onDoubleClick(View v) {
    counter++;
    textView.setText(counter+""); 
}

相关链接：

您可以在此处查看完整的工作代码

于 2019-01-26T15:41:27.600 回答
0

虽然我喜欢原始答案中方法的简单性

这是我的版本

public abstract class OnDoubleClickListener implements View.OnClickListener {

    private static final int TIME_OUT = ViewConfiguration.getDoubleTapTimeout();
    private TapHandler tapHandler = new TapHandler();

    public abstract void onSingleClick(View v);
    public abstract void onDoubleClick(View v);

    @Override
    public void onClick(View v) {
        tapHandler.cancelSingleTap(v);
        if (tapHandler.isDoubleTap()){
            onDoubleClick(v);
        } else {
            tapHandler.performSingleTap(v);
        }
    }

    private class TapHandler implements Runnable {
        public boolean isDoubleTap() {
            final long tapTime = System.currentTimeMillis();
            boolean doubleTap = tapTime - lastTapTime < TIME_OUT;
            lastTapTime = tapTime;
            return doubleTap;
        }
        public void performSingleTap(View v) {
            view = v;
            v.postDelayed(this, TIME_OUT);
        }
        public void cancelSingleTap(View v) {
            view = null;
            v.removeCallbacks(this);
        }

        @Override
        public void run() {
            if (view != null) {
                onSingleClick(view);
            }
        }
        private View view;
        private long lastTapTime = 0;
    }
}

用法与原版相同

view.setOnClickListener(new OnDoubleClickListener() {

    @Override
    public void onSingleClick(View v) {

    }

    @Override
    public void onDoubleClick(View v) {

    }
});
于 2021-01-14T05:07:13.330 回答
0

我用来实现相同功能的等效 C# 代码，甚至可以自定义以接受 N 个 Taps

public interface IOnTouchInterface
{
    void ViewTapped();
}

public class MultipleTouchGestureListener : Java.Lang.Object, View.IOnTouchListener
{
    int clickCount = 0;
    long startTime;
    static long MAX_DURATION = 500;
    public int NumberOfTaps { get; set; } = 7;

    readonly IOnTouchInterface interfc;

    public MultipleTouchGestureListener(IOnTouchInterface tch)
    {
        this.interfc = tch;
    }

    public bool OnTouch(View v, MotionEvent e)
    {
        switch (e.Action)
        {
            case MotionEventActions.Down:
                clickCount++;
                if(clickCount == 1)
                    startTime = Utility.CurrentTimeSince1970;
                break;
            case MotionEventActions.Up:
                var currentTime = Utility.CurrentTimeSince1970;
                long time = currentTime - startTime;
                if(time <= MAX_DURATION * NumberOfTaps)
                {
                    if (clickCount == NumberOfTaps)
                    {
                        this.interfc.ViewTapped();
                        clickCount = 0;
                    }
                }
                else
                {
                    clickCount = 0;
                }
                break;
        }
        return true;
    }
}

public static class Utility
{
    public static long CurrentTimeSince1970
    {
        get
        {
            DateTime dt = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Local);
            DateTime dtNow = DateTime.Now;
            TimeSpan result = dtNow.Subtract(dt);
            long seconds = (long)result.TotalMilliseconds;
            return seconds;
        }
    }
}

目前，上述代码在引发 View Tapped 事件之前接受 7 作为点击次数。但它可以用任何数字定制

于 2018-01-30T04:08:06.483 回答
0

我已经使用kotlin 协程实现了一个简单的自定义方法（对于 java 可以通过线程完成）。

var click = 0

view.setOnClickListener{
   click++
   clicksHandling()
}

fun clicksHandling() {
   if (click == 1) {
      launch {
        delay(300) // custom delay duration between clicks
        // if user didn't double tap then click counter still 1
        if (click == 1) {
          // single click handling
          runOnUiThread {
             // whatever you wanna do on UI thread
          }
        }

        click = 0 //reset counter , this will run no matter single / double tap
      }
   //double click handling
   if (click == 2) {
         // whatever on double click
   }
}
于 2018-12-11T09:24:10.780 回答
0

在 Kotlin 你可以试试这个，

就像我使用cardview进行点击一样，

（例如：双击我喜欢和不喜欢。）

cardviewPostCard.setOnClickListener(object : DoubleClickListener() {
    override fun onDoubleClick(v: View?) {

        if (holder.toggleButtonLike.isChecked) {
            holder.toggleButtonLike.setChecked(false) //
        } else {
            holder.toggleButtonLike.setChecked(true)

        }
    }
})

这是您的 DoubleClickListener 类，

abstract class DoubleClickListener : View.OnClickListener {
    var lastClickTime: Long = 0
    override fun onClick(v: View?) {
        val clickTime = System.currentTimeMillis()
        if (clickTime - lastClickTime < DOUBLE_CLICK_TIME_DELTA) {
            onDoubleClick(v)
        }
        lastClickTime = clickTime
    }

    abstract fun onDoubleClick(v: View?)

    companion object {
        private const val DOUBLE_CLICK_TIME_DELTA: Long = 300 //milliseconds
    }
}
于 2021-01-07T10:19:27.627 回答
0

在 Kotlin 中执行此操作的简单方法：

button.setOnTouchListener(object : View.OnTouchListener{
    val gestureDetector = GestureDetector(object : GestureDetector.SimpleOnGestureListener(){
        override fun onDoubleTap(e: MotionEvent?): Boolean {
           //do something here
            return super.onDoubleTap(e)
        }
    })

    override fun onTouch(v: View?, event: MotionEvent?): Boolean {
        //do something here
        gestureDetector.onTouchEvent(event)
        return true
    }
})
于 2020-07-16T16:38:46.590 回答
0

GestureDetectorCompat您可以使用该类实现双击。在此示例中，当双击 textview 时，您可以执行您的逻辑。

public class MainActivity extends AppCompatActivity {

GestureDetectorCompat gestureDetectorCompat;
TextView textElement;

@Override
protected void onCreate(Bundle savedInstanceState) { 
    .....
    textElement = findViewById(R.id.textElement);
    gestureDetectorCompat = new GestureDetectorCompat(this, new MyGesture());
    textElement.setOnTouchListener(onTouchListener);

}

 View.OnTouchListener onTouchListener = new View.OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        gestureDetectorCompat.onTouchEvent(event);
        return true;
    }
};
    class MyGesture extends GestureDetector.SimpleOnGestureListener {

    @Override
    public boolean onDown(MotionEvent e) {
        return true;
    }

    @Override
    public boolean onDoubleTap(MotionEvent e) {
        // whatever on double click
        return true;
    }
}
于 2019-02-21T19:42:45.567 回答
0

要检测手势点击的类型，可以实现一些内联的东西（这里projectText是一个EditText）：

projectText.setOnTouchListener(new View.OnTouchListener() {
    private GestureDetector gestureDetector = new GestureDetector(activity, new GestureDetector.SimpleOnGestureListener() {
        @Override
        public boolean onDoubleTap(MotionEvent e) {
            projectText.setInputType(InputType.TYPE_CLASS_TEXT);
            activity.getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_VISIBLE);
            return super.onDoubleTap(e);
        }
        @Override
        public boolean onSingleTapUp(MotionEvent e) {
                projectText.setInputType(InputType.TYPE_NULL); // disable soft input
                final int itemPosition = getLayoutPosition();
                if(!projects.get(itemPosition).getProjectId().equals("-1"))
                    listener.selectedClick(projects.get(itemPosition));

            return super.onSingleTapUp(e);
        }
    });

    @Override
    public boolean onTouch(View v, MotionEvent event) {
        gestureDetector.onTouchEvent(event);
        return false; //true stops propagation of the event
    }
});
于 2020-11-08T22:32:51.793 回答
0

bughi & Jayant Arora 为 copypast 提供的解决方案：

public abstract class DoubleClickListener implements View.OnClickListener {
private int position;
private Timer timer;

private static final long DOUBLE_CLICK_TIME_DELTA = 300;//milliseconds

long lastClickTime = 0;

public DoubleClickListener (int position) {
    this.position = position;
}

@Override
public void onClick(View v) {
    long clickTime = System.currentTimeMillis();
    if (clickTime - lastClickTime < DOUBLE_CLICK_TIME_DELTA){
        if (timer != null) {
            timer.cancel(); //Cancels Running Tasks or Waiting Tasks.
            timer.purge();  //Frees Memory by erasing cancelled Tasks.
        }
        onDoubleClick(v, position);
    } else {
        final Handler handler = new Handler();
        final Runnable mRunnable = () -> {
            onSingleClick(v, position);
        };
        TimerTask timertask = new TimerTask() {
            @Override
            public void run() {
                handler.post(mRunnable);
            }
        };
        timer = new Timer();
        timer.schedule(timertask, DOUBLE_CLICK_TIME_DELTA);

    }
    lastClickTime = clickTime;
}

public abstract void onSingleClick(View v, int position);
public abstract void onDoubleClick(View v, int position);}
于 2016-06-16T11:26:09.603 回答
0

我创建了一个简单的库来处理这个问题。它还可以检测到两次以上的点击（这完全取决于您）。导入ClickCounter 类后，您可以使用它来检测单次和多次点击：

ClickCounter counter = new ClickCounter();


view.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        counter.addClick();  // submits click to be counted
    }
});

counter.setClickCountListener(new ClickCounter.ClickCountListener() {
    @Override
    public void onClickingCompleted(int clickCount) {
        rewardUserWithClicks(clickCount); // Thats All!!
    }
});
于 2020-12-15T09:35:18.520 回答