8

我有一个由两个字符串和一个枚举组成的类。我正在尝试将此类的实例用作字典中的键。不幸的是，我似乎没有正确实施 IEquatable。这是我的做法：

public enum CoinSide
{
    Heads,
    Tails
}

public class CoinDetails : IComparable, IEquatable<CoinDetails>
{
    private string denomination;
    private string design;
    private CoinSide side;

//...

    public int GetHashCode(CoinDetails obj)
    {
        return string.Concat(obj.Denomination, obj.Design, obj.Side.ToString()).GetHashCode();
    }

    public bool Equals(CoinDetails other)
    {
        return (this.Denomination == other.Denomination && this.Design == other.Design && this.Side == other.Side);
    }
}

但是，我似乎仍然无法在我的字典中查找项目。此外，以下测试失败：

    [TestMethod]
    public void CoinDetailsHashCode()
    {
        CoinDetails a = new CoinDetails("1POUND", "1997", CoinSide.Heads);
        CoinDetails b = new CoinDetails("1POUND", "1997", CoinSide.Heads);
        Assert.AreEqual(a.GetHashCode(), b.GetHashCode());
    }

    [TestMethod]
    public void CoinDetailsCompareForEquality()
    {
        CoinDetails a = new CoinDetails("1POUND", "1997", CoinSide.Heads);
        CoinDetails b = new CoinDetails("1POUND", "1997", CoinSide.Heads);
        Assert.AreEqual<CoinDetails>(a, b);
    }

有人能指出我哪里出错了吗？我确定我错过了一些相当简单的东西，但我不确定是什么。

4

1 回答 1

8

您的班级必须覆盖Equalsand GetHashCode：

public class CoinDetails 
{
    private string Denomination;
    private string Design;
    private CoinSide Side;

    public override bool Equals(object obj)
    {
        CoinDetails c2 = obj as CoinDetails;
        if (c2 == null)
            return false;
        return Denomination == c2.Denomination && Design == c2.Design;
    }

    public override int GetHashCode()
    {
        unchecked
        {
            int hash = 17;
            hash = hash * 23 + (Denomination ?? "").GetHashCode();
            hash = hash * 23 + (Design ?? "").GetHashCode();
            return hash;
        }
    }
}

请注意，我还GetHashCode根据以下内容改进了您的算法：什么是覆盖 System.Object.GetHashCode 的最佳算法？

您还可以将自定义传递IEqualityComparer<CoinDetail>给字典：

public class CoinComparer : IEqualityComparer<CoinDetails>
{
    public bool Equals(CoinDetails x, CoinDetails y)
    {
        if (x == null || y == null) return false;
        if(object.ReferenceEquals(x, y)) return true;
        return x.Denomination == y.Denomination && x.Design == y.Design;
    }

    public int GetHashCode(CoinDetails obj)
    {
        unchecked
        {
            int hash = 17;
            hash = hash * 23 + (obj.Denomination ?? "").GetHashCode();
            hash = hash * 23 + (obj.Design ?? "").GetHashCode();
            return hash;
        }
    }                      
}

现在这有效并且不需要CoinDetails覆盖Equals+ GetHashCode：

var dict = new Dictionary<CoinDetails, string>(new CoinComparer());
dict.Add(new CoinDetails("1POUND", "1997"), "");
dict.Add(new CoinDetails("1POUND", "1997"), ""); // FAIL!!!!
于 2014-03-04T15:00:57.413 回答