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我正在开发一个应用程序，我需要用户 SIM 卡、电话号码、imei 号码和运营商的详细信息。到目前为止，我已经参考这个答案获得了他的 IMEI 号码，是他的设备单卡还是双卡。我如何获得他的 SIM 卡号码和两个连接的运营商名称。

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4 回答 4

3

试试这个，对我有用：

TelephonyManager manager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
String carrierName = manager.getNetworkOperatorName();
于 2014-07-16T16:22:15.293 回答
3

幸运的是，有几种原生解决方案。希望这会对某人有所帮助。

对于 API >=17：

TelephonyManager manager = (TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE);

// Get information about all radio modules on device board
// and check what you need by calling #getCellIdentity.

final List<CellInfo> allCellInfo = manager.getAllCellInfo();
for (CellInfo cellInfo : allCellInfo) {
    if (cellInfo instanceof CellInfoGsm) {
        CellIdentityGsm cellIdentity = ((CellInfoGsm) cellInfo).getCellIdentity();
        //TODO Use cellIdentity to check MCC/MNC code, for instance.
    } else if (cellInfo instanceof CellInfoWcdma) {
        CellIdentityWcdma cellIdentity = ((CellInfoWcdma) cellInfo).getCellIdentity();
    } else if (cellInfo instanceof CellInfoLte) {
        CellIdentityLte cellIdentity = ((CellInfoLte) cellInfo).getCellIdentity();
    } else if (cellInfo instanceof CellInfoCdma) {
        CellIdentityCdma cellIdentity = ((CellInfoCdma) cellInfo).getCellIdentity();
    } 
}

在 AndroidManifest 添加权限：

<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    <uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
</manifest>

要获得网络运营商，您可以检查 mcc 和 mnc 代码：

对于 API >=22：

final SubscriptionManager subscriptionManager = SubscriptionManager.from(context);
final List<SubscriptionInfo> activeSubscriptionInfoList = subscriptionManager.getActiveSubscriptionInfoList();
for (SubscriptionInfo subscriptionInfo : activeSubscriptionInfoList) {
    final CharSequence carrierName = subscriptionInfo.getCarrierName();
    final CharSequence displayName = subscriptionInfo.getDisplayName();
    final int mcc = subscriptionInfo.getMcc();
    final int mnc = subscriptionInfo.getMnc();
    final String subscriptionInfoNumber = subscriptionInfo.getNumber();
}

对于 API >=23。只检查手机是否为双/三/多卡：

TelephonyManager manager = (TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE);
if (manager.getPhoneCount() == 2) {
    // Dual sim
}
于 2016-11-05T15:07:14.300 回答
1 
        // Use this code, it will provide all the info realated both sim card 

        Required Permission:
        <uses-permission android:name="android.permission.READ_PHONE_STATE"/> 

            if (getSimInfo(context).get(0) != null) {  // SIM 1
                               getSimInfo(context).get(0).getMcc()); 
                               getSimInfo(context).get(0).getMnc());
                            } else {
                               Log.d("Sim card", "Sim card not available");
                            }
                            if (getSimInfo(context).get(1) != null) { // SIM 2
                                getSimInfo(context).get(1).getMcc());
                                getSimInfo(context).get(1).getMnc());
                            } else {
                               Log.d("Sim card", "Sim card not available");
                            }
                            if (getNetworkOperator(context).get(0) != null) { // SIM 1
     (String)getSimInfo(context).get(0).getCarrierName());
                            } else {
                               Log.d("Sim card", "Sim card not available");
                            }
                            if (getNetworkOperator(context).get(1) != null) {// SIM 2 
 (String)getSimInfo(context).get(1).getCarrierName());
                            } else {
                              Log.d("Sim card", "Sim card not available");
                            }

        // getSimInfo
        public List<SubscriptionInfo> getSimInfo(Context context) {
                SubscriptionManager subManager = (SubscriptionManager) context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE);
                List<SubscriptionInfo> subscriptionInfoList = new ArrayList<>();
                subscriptionInfoList = subManager.getActiveSubscriptionInfoList();
                Log.d("LIST LIST", subscriptionInfoList.toString());
                if (subscriptionInfoList == null) {
                    Toast.makeText(context, "address not found", Toast.LENGTH_SHORT).show();
                }
                return subscriptionInfoList;
            }

            // getNetworkOperator 
            public List<String> getNetworkOperator(final Context context) {
                // Get System TELEPHONY service reference
                List<String> carrierNames = new ArrayList<>();
                try {
                    final String permission = android.Manifest.permission.READ_PHONE_STATE;
                    if ((Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) && (ContextCompat.checkSelfPermission(context, permission) == PackageManager.PERMISSION_GRANTED)) {
                        final List<SubscriptionInfo> subscriptionInfos = SubscriptionManager.from(context).getActiveSubscriptionInfoList();
                        for (int i = 0; i < subscriptionInfos.size(); i++) {
                            carrierNames.add(subscriptionInfos.get(i).getCarrierName().toString());
                        }

                    } else {
                        TelephonyManager telephonyManager = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
                        // Get carrier name (Network Operator Name)
                        carrierNames.add(telephonyManager.getNetworkOperatorName());
            enter code here
                    }
                } catch (Exception e) {
                    e.printStackTrace();
                }
                return carrierNames;
            }
于 2019-01-25T07:38:42.613 回答
1

在这里尝试：

private List<String> getNetworkOperator(final Context context) {
    // Get System TELEPHONY service reference
    List<String> carrierNames = new ArrayList<>();
    try {
        final String permission = Manifest.permission.READ_PHONE_STATE;
        if ( (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) && (ContextCompat.checkSelfPermission(context, permission) == PackageManager.PERMISSION_GRANTED) ){
            final List<SubscriptionInfo> subscriptionInfos = SubscriptionManager.from(context).getActiveSubscriptionInfoList();
            for (int i = 0; i < subscriptionInfos.size(); i++) {
                carrierNames.add(subscriptionInfos.get(i).getCarrierName().toString());
            }

        } else {
            TelephonyManager telephonyManager = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
            // Get carrier name (Network Operator Name)
            carrierNames.add(telephonyManager.getNetworkOperatorName());

        }
    } catch (Exception e) {
        e.printStackTrace();
    }
    return carrierNames;
}
于 2016-10-26T10:11:43.020 回答