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我用matlab创建了很多本地二进制模式的实现，我对它们有点困惑。

维基百科解释了基本的 LBP是如何工作的：

1- Divide the examined window into cells (e.g. 16x16 pixels for each cell).
2- For each pixel in a cell, compare the pixel to each of its 8 neighbors (on its left-top, left-middle, left-bottom, right-top, etc.). Follow the pixels along a circle, i.e. clockwise or counter-clockwise.
3- Where the center pixel's value is greater than the neighbor's value, write "1". Otherwise, write "0". This gives an 8-digit binary number (which is usually converted to decimal for convenience).
4- Compute the histogram, over the cell, of the frequency of each "number" occurring (i.e., each combination of which pixels are smaller and which are greater than the center).
5- Optionally normalize the histogram.
6- Concatenate (normalized) histograms of all cells. This gives the feature vector for the window.

看看这个算法，我可以得出结论，每个 LBP 特征向量都有 num_cels*256 个维度，其中 num_cels 是图像的 16x16 像素单元的数量。每个单元格将有 256 个可能的值（0 到 255），因此特征向量的大小可以变化很大。

但是，查看一些 LBP 实现，VLFEAT_LBP返回一个矩阵而不是特征向量。在这个实现中，LBP 作为 256 个特征向量返回，我认为（不确定）是所有单元格的所有直方图的总和。我只想知道：这是经典的LBP解释和matlab源代码。

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1 回答 1

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% clc;    % Clear the command window.
% close all;  % Close all figures (except those of imtool.)
% imtool close all;  % Close all imtool figures.
% clear;  % Erase all existing variables.
% workspace;  % Make sure the workspace panel is showing.
% fontSize = 20;
% % Read in a standard MATLAB gray scale demo image.
% folder = fullfile(matlabroot, '\toolbox\images\imdemos');
% baseFileName = 'cameraman.tif';
% % Get the full filename, with path prepended.
% fullFileName = fullfile(folder, baseFileName);
% if ~exist(fullFileName, 'file')
%   % Didn't find it there.  Check the search path for it.
%   fullFileName = baseFileName; % No path this time.
%   if ~exist(fullFileName, 'file')
%       % Still didn't find it.  Alert user.
%       errorMessage = sprintf('Error: %s does not exist.', fullFileName);
%       uiwait(warndlg(errorMessage));
%       return;
%   end
% end
grayImage = imread('fig.jpg');
% Get the dimensions of the image.  numberOfColorBands should be = 1.
[rows columns numberOfColorBands] = size(grayImage);

% Display the original gray scale image.
subplot(2, 2, 1);
imshow(grayImage, []);
%title('Original Grayscale Image', 'FontSize', fontSize);
% Enlarge figure to full screen.
set(gcf, 'Position', get(0,'Screensize')); 
set(gcf,'name','Image Analysis Demo','numbertitle','off') 
% Let's compute and display the histogram.
[pixelCount grayLevels] = imhist(grayImage);
subplot(2, 2, 2); 
bar(pixelCount);
%title('Histogram of original image', 'FontSize', fontSize);
xlim([0 grayLevels(end)]); % Scale x axis manually.
% Preallocate/instantiate array for the local binary pattern.
localBinaryPatternImage = zeros(size(grayImage));
for row = 2 : rows - 1   
    for col = 2 : columns - 1    
        centerPixel = grayImage(row, col);
        pixel7=grayImage(row-1, col-1) > centerPixel;  
        pixel6=grayImage(row-1, col) > centerPixel;   
        pixel5=grayImage(row-1, col+1) > centerPixel;  
        pixel4=grayImage(row, col+1) > centerPixel;     
        pixel3=grayImage(row+1, col+1) > centerPixel;    
        pixel2=grayImage(row+1, col) > centerPixel;      
        pixel1=grayImage(row+1, col-1) > centerPixel;     
        pixel0=grayImage(row, col-1) > centerPixel;       
        localBinaryPatternImage(row, col) = uint8(...
            pixel7 * 2^7 + pixel6 * 2^6 + ...
            pixel5 * 2^5 + pixel4 * 2^4 + ...
            pixel3 * 2^3 + pixel2 * 2^2 + ...
            pixel1 * 2 + pixel0);
    end  
end 
subplot(2,2,3);
imshow(localBinaryPatternImage, []);
%title('Local Binary Pattern', 'FontSize', fontSize);
subplot(2,2,4);
[pixelCounts, GLs] = imhist(uint8(localBinaryPatternImage));
bar(GLs, pixelCounts);
%title('Histogram of Local Binary Pattern', 'FontSize', fontSize);
于 2015-10-10T14:19:03.683 回答