5

这是正确的方法吗?

DELETE t1, t2, t3, t4 FROM 
  table1 as t1 
  INNER JOIN  table2 as t2 on t1.id = t2.id
  INNER JOIN  table3 as t3 on t1.id=t3.id
  INNER JOIN  table4 as t4 on t1.id=t4.id
  WHERE  t1.username='%s' AND t1.id='%s'
4

3 回答 3

14

对,那是正确的。它在这里工作正常:

CREATE TABLE table1 (id int, username nvarchar(30));
CREATE TABLE table2 (id int);
CREATE TABLE table3 (id int);
CREATE TABLE table4 (id int);

INSERT INTO table1 VALUES (1, 'Foo'),(2, 'Bar');
INSERT INTO table2 VALUES (1),(2);
INSERT INTO table3 VALUES (1),(2);
INSERT INTO table4 VALUES (1),(2);

SELECT COUNT(*) FROM table1;
2
SELECT COUNT(*) FROM table2;
2
SELECT COUNT(*) FROM table3;
2
SELECT COUNT(*) FROM table4;
2

DELETE t1, t2, t3, t4 FROM
  table1 as t1
  INNER JOIN  table2 as t2 on t1.id = t2.id
  INNER JOIN  table3 as t3 on t1.id=t3.id
  INNER JOIN  table4 as t4 on t1.id=t4.id
  WHERE  t1.username='Foo' AND t1.id='1';

SELECT COUNT(*) FROM table1;
1
SELECT COUNT(*) FROM table2;
1
SELECT COUNT(*) FROM table3;
1
SELECT COUNT(*) FROM table4;
1

如果它不适合您,也许您可​​以修改此示例以显示您遇到的问题。

于 2010-02-06T20:08:30.567 回答
5

一个简单的方法是先把它写成一个查询:

SELECT * FROM 
        table1 as t1 
        INNER JOIN  table2 as t2 on t1.id = t2.id
        INNER JOIN  table3 as t3 on t1.id=t3.id
        INNER JOIN  table4 as t4 on t1.id=t4.id
        WHERE  t1.username='%s' AND t1.id='%s'

如果您得到您期望的结果,只需将 *Select ** 替换为 Delete 和您的表名。那么它会变成:

Delete t1, t2, t3, t4 From table1 as t1 
        INNER JOIN  table2 as t2 on t1.id = t2.id
        INNER JOIN  table3 as t3 on t1.id=t3.id
        INNER JOIN  table4 as t4 on t1.id=t4.id
        WHERE  t1.username='%s' AND t1.id='%s'
于 2010-02-06T19:51:11.047 回答
1

通过以下方式使其变得简单:

DELETE FROM `Table1` t1, `Table2` t2 USING t1, t2
WHERE t1.`id` =  t2.`id` AND t1.`id` = 10; <br>

享受 :)

于 2014-06-26T14:58:01.500 回答