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如果单击接受或取消,我只需要显示一个祝酒词,但无法理解为什么错误如何解决?错误出现在吐司上,getapplicationcontext() 我了解 android 上的对话框和吐司

    import android.app.AlertDialog;
    import android.app.Dialog;
    import android.content.DialogInterface;
    import android.os.Bundle;
    import android.support.v4.app.DialogFragment;
    import android.util.Log;
    import android.widget.Toast;

    public class confirmacion extends DialogFragment {
    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState){
        AlertDialog.Builder builder= new AlertDialog.Builder(getActivity());
        builder.setMessage("Confirmar?").setTitle("confirmacion")
        .setPositiveButton("aceptar", new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {
    Log.i("dialogos","aceptado");
    dialog.cancel();
    Toast.makeText(getApplicationContext(), "Eliminacion fallida.", Toast.LENGTH_LONG).show();

            }


        }).setNegativeButton("cancelar", new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {
    Log.i("dialogos","cancelada");
    dialog.cancel();
            }
        });

        return builder.create();

    }

    }
4

1 回答 1

6

从改变

Toast.makeText(getApplicationContext(), "Eliminacion fallida.", Toast.LENGTH_LONG).show();

Toast.makeText(getActivity(), "Eliminacion fallida.", Toast.LENGTH_LONG).show();
于 2014-03-01T11:44:05.640 回答