我正在尝试使用 rabbit 4000 处理器旋转步进电机。我有一个保存结构的队列,并创建了一个函数来创建运行 4 绕组步进电机所需的二进制位序列。我试图将序列从结构中的函数传递给将用它填充队列的生产者。问题是我没有将预期值放入队列中。我是否误解了如何从函数返回结构,还是需要单独分配数组值?相关的代码块是:
typedef struct {
char d[4];
int delayUs;
} mQueueEntry_t;
mQueueEntry_t setDirStep(int count0, int count1, int count2, int count3){
mQueueEntry_t entry;
entry.d[0] = (!((count0+1)%4)); //1a
entry.d[1] = (!((count1+1)%4)); //1b
entry.d[2] = (!((count2+1)%4)); //2a
entry.d[3] = (!((count3+1)%4)); //2b
entry.delayUs =10;
printf("Breaking Funct with: %d,%d,%d,%d\n",entry.d[0], entry.d[1], entry.d[2], entry.d[3]);
}
// continually stuff a queue with a dedicated structure
void Producer(void* pdata){
mQueueEntry_t entry;
int count0 = 3;
int count1=1;
int count2=2;
int count3=0;
labQueue_t * q = (labQueue_t *) pdata; // Note use of task data..
printf("Hola Producer\n");
while (1)
{
entry = setDirStep(count0, count1, count2, count3);
printf("Values after funct call: %d,%d,%d,%d\n",entry.d[0], entry.d[1], entry.d[2], entry.d[3]);
count0++;
count1++;
count2++;
count3++;
// send a copy of the element and
switch ( labQueuePut( q, &entry) ){
case LABQ_OK:
printf("put %d,%d,%d,%d\n",entry.d[0], entry.d[1], entry.d[2], entry.d[3]);
break;
case LABQ_TIMEOUT:
OSTimeDly(OS_TICKS_PER_SEC/10);
break;
case LABQ_FULL:
OSTimeDly(OS_TICKS_PER_SEC/10);
break;
default:
assert(0);
break;
}
OSTimeDly(1);
}
}
程序的屏幕输出:
Hola Consumer
Hola Producer
Breaking Funct with: 1,0,0,0 函数
调用后的值:收到 235,0,24,23
(1a= 0: 1b= 1: 2a= 0:2b= 0) 0
put 235,0 ,24,23
中断函数
:0,0,1,0 函数调用后的值:
收到 236,41,237,0 (1a= 0: 1b= 0: 2a= 0:2b= 1) 1
put 236,41,237,0
我的问题是函数调用后从破坏函数到值的值应该是相同的。