11

如何使用Jasypt库解密加密密码？

package com.uk.mysqlmaven.jsf.test;

import org.jasypt.util.password.StrongPasswordEncryptor;
import org.jasypt.util.text.StrongTextEncryptor;


public class PasswordEncryptionDecryptionUsingJASYPT {
    public static void main(String[] args) {
        try {
            String password = "password";
            StrongPasswordEncryptor encryptor = new StrongPasswordEncryptor();
            String encryptedPassword = encryptor.encryptPassword(password);
            if (encryptor.checkPassword(password, encryptedPassword)) {
                //correct
                System.out.println("Encrypted: "+ encryptedPassword);
            } else {
                //bad again
                System.out.println("Error: ");
            }
            StrongTextEncryptor textEncryptor = new StrongTextEncryptor();
            textEncryptor.setPassword(encryptedPassword);
            String decryptedPassword = textEncryptor.decrypt(encryptedPassword);
            System.out.println("Decrypted: "+ decryptedPassword);
            
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

尝试解密密码时在控制台中显示错误：

Encrypted: JIOYXNa1+3+QefY2S7sas7LmhyOuDQcG8TTsQoTkqj0OtobCvwAFHXxoTr7z6HuP
org.jasypt.exceptions.EncryptionOperationNotPossibleException: Encryption raised an exception. A possible cause is you are using strong encryption algorithms and you have not installed the Java Cryptography Extension (JCE) Unlimited Strength Jurisdiction Policy Files in this Java Virtual Machine
    at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.handleInvalidKeyException(StandardPBEByteEncryptor.java:999)
    at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.decrypt(StandardPBEByteEncryptor.java:976)
    at org.jasypt.encryption.pbe.StandardPBEStringEncryptor.decrypt(StandardPBEStringEncryptor.java:725)
    at org.jasypt.util.text.StrongTextEncryptor.decrypt(StrongTextEncryptor.java:118)
    at com.uk.mysqlmaven.jsf.test.PasswordEncryptionDecryptionUsingJASYPT.main(PasswordEncryptionDecryptionUsingJASYPT.java:22)
4

2 回答 2

13

你可以试试下面的例子。这对你有用：请始终保持 mpCryptoPassword 值非常机密的位置，只有应用程序才能读取它。

public class EncryptionDecryptionUsingJASYPT {

    private static String mpCryptoPassword = "BornToFight";

    public static void main(String[] args) {
        String value = "Original Text: Eclipse";

        System.out.println("Original Value : "+value);
        StandardPBEStringEncryptor encryptor = new StandardPBEStringEncryptor();
        encryptor.setPassword(mpCryptoPassword);
        String encryptedPassword = encryptor.encrypt(value);
        System.out.println(encryptedPassword);

        StandardPBEStringEncryptor decryptor = new StandardPBEStringEncryptor();
        decryptor.setPassword(mpCryptoPassword);
        System.out.println(decryptor.decrypt(encryptedPassword));
    }
}
于 2016-09-05T12:42:36.637 回答
2

从命令生成的加密字符串没有给出预期的结果，因为它不能加密像“！”这样的特殊字符。并给出错误“未找到事件”

KAD@ashutosh MINGW64 ~/桌面

$ java -cp ~/.m2/repository/org/jasypt/jasypt/1.9.3/jasypt-1.9.3.jar org.jasypt.intf.cli.JasyptPBEStringEncryptionCLI input="Test!email30#password" password="some_salt " 算法=PBEWithMD5AndDES

bash: !email30#password: 找不到事件

这是一个使用org.jasypt.util.text.AES256TextEncryptor This is a utility class for easy execution的示例high-strength encryption of texts。

此类在内部以StandardPBEStringEncryptor这种方式配置：

  • 算法：PBEWithHMACSHA512AndAES_256。

  • 关键获取迭代：1000.

使用它所需的步骤是：

  1. 创建一个实例（使用新的）。
  2. 设置密码（使用 setPassword(String) 或 setPasswordCharArray(char[])）。
  3. 执行所需的加密（字符串）或解密（字符串）操作。

pom.xml：

<dependency>
        <groupId>com.github.ulisesbocchio</groupId>
        <artifactId>jasypt-spring-boot-starter</artifactId>
        <version>2.1.2</version>
    </dependency>

您可以使用 jasypt 最新的 2.1.2（带引导 2.1.1）或jasypt-1.9.3.jar.

Java代码：

import org.jasypt.util.text.AES256TextEncryptor;
import java.security.NoSuchAlgorithmException;

public class JasyptPasswordEcryptor {
 public static void main(String[] args) throws NoSuchAlgorithmException {

    String password = "Test!email30#password";

    AES256TextEncryptor encryptor = new AES256TextEncryptor();
    encryptor.setPassword("some_salt");
    String myEncryptedText = encryptor.encrypt(password);
    System.out.println("Encrypted: "+myEncryptedText);

    String plainText = encryptor.decrypt(myEncryptedText);
    System.out.println("Decrypted: "+plainText);
 }
}

输出：

加密：fureWQHrflMinY+KBOcNeJyYmQv+7Ung/IclGz3iSBYKqTNdgslADg+TMcfFI/unaqZ/P3kDGPco2jZ4vIhrFw==

解密：Test!email30#password

Spring Boot 集成：

您可以@EnableEncryptableProperties在任何配置类或@SpringBootApplication. 参见示例：

import com.ulisesbocchio.jasyptspringboot.annotation.EnableEncryptableProperties;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.autoconfigure.domain.EntityScan;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.transaction.annotation.EnableTransactionManagement;

@EnableEncryptableProperties
@SpringBootApplication
@ComponentScan(basePackages = {"com.company"})
@EntityScan(basePackages = {"com.company.persistence.entities"})
@EnableJpaRepositories(value = {"com.company.persistence.repository"})
@EnableTransactionManagement
public class Application {

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }

}

在任何属性/yml 文件中：

email:
    password:
        # DO-NOT-USE/REMOVE THIS
        plain: 'Test!email30#password'
        # use this encrypted one
        encrypted: ENC(fureWQHrflMinY+KBOcNeJyYmQv+7Ung/IclGz3iSBYKqTNdgslADg+TMcfFI/unaqZ/P3kDGPco2jZ4vIhrFw==)

jasypt:
    encryptor:
        password: some_salt
于 2019-10-29T06:02:16.903 回答