3

我将 RSS.NET 用于 .NET 2.0。尽我所能,我得到以下 0 个频道:

feed = RssFeed.Read("http://feeds.feedburner.com/punchfire?format=xml");

我注意到,对于其他提要,这有效,例如

feed = RssFeed.Read("http://www.engadget.com/rss.xml");

我想它必须是一个有效的xml文档。你认为我应该在我的应用程序代码中检查“.xml”还是有什么方法可以调整RSS.NET以接受feedburner提要?

4

4 回答 4

2

您无法获得任何通道节点的原因是,原子格式没有任何通道节点。检查以下

您的第二个链接是 Rss Feed,其中包含如下频道节点

<rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd">
<channel>
<title>Engadget</title>
<link>http://www.engadget.com</link>
 .
 .
 .

另一方面,原子提要不使用通道节点,正如您通过上面的规范链接可能理解的那样。

<?xml version="1.0" encoding="utf-8"?>
   <feed xmlns="http://www.w3.org/2005/Atom">
     <title type="text">dive into mark</title>
     <subtitle type="html">
       A &lt;em&gt;lot&lt;/em&gt; of effort
       went into making this effortless
     </subtitle>
     <updated>2005-07-31T12:29:29Z</updated>
     <id>tag:example.org,2003:3</id>
     <link rel="alternate" type="text/html"
      hreflang="en" href="http://example.org/"/>
     <link rel="self" type="application/atom+xml"
      href="http://example.org/feed.atom"/>
     <rights>Copyright (c) 2003, Mark Pilgrim</rights>
     <generator uri="http://www.example.com/" version="1.0">
       Example Toolkit
     </generator>
     <entry>
      .
      .
      .

编辑:检查提要格式

    // url of the feed 
    string utlToload = @"http://feeds.feedburner.com/punchfire?format=xml"



    // load feed
        Argotic.Syndication.GenericSyndicationFeed feed = 
Argotic.Syndication.GenericSyndicationFeed.Create(new Uri(urlToLoad));

        // check what format is it
        if (feed.Format.Equals(SyndicationContentFormat.Rss))
        {
            // yourlogic here
        }
        else if (feed.Format.Equals(SyndicationContentFormat.Atom))
        {
            // yourlogic here
        } 
        else if (feed.Format.Equals(SyndicationContentFormat.NewsML))
        {
            // yourlogic here
        } 

希望能帮助到你

于 2010-02-04T11:13:57.267 回答
1

使用 .Net 3.5+,解析 Atom 提要非常容易。顺便说一句,我听说 Atom 提要是 RSS 的新标准。

public class RssFeedDO
{
    public string RssFeedUrl { get; private set; }

    /// <summary>
    /// Build feed processor
    /// </summary>
    /// <param name="feedUrl">Atom or RSS url with http in front.</param>
    public RssFeedDO(string feedUrl)
    {
        this.RssFeedUrl = feedUrl;
    }

    /// <summary>
    /// Will try to get RSS data from url passed in constructor. Can do atom or rss
    /// </summary>
    /// <returns></returns>
    public SyndicationFeed GetRSSData()
    {
        SyndicationFeed feed = null;

        XmlReaderSettings settings = new XmlReaderSettings();
        settings.IgnoreWhitespace = true;
        settings.CheckCharacters = true;
        settings.CloseInput = true;
        settings.IgnoreComments = true;
        settings.IgnoreProcessingInstructions = true;
        settings.DtdProcessing = DtdProcessing.Prohibit;

        if (!string.IsNullOrEmpty(this.RssFeedUrl))
        {
            using (XmlReader reader = XmlReader.Create(this.RssFeedUrl, settings))
            {
                SyndicationFeedFormatter GenericFeedFormatter = null;
                Atom10FeedFormatter atom = new Atom10FeedFormatter();
                Rss20FeedFormatter rss = new Rss20FeedFormatter();

                if (reader.ReadState == ReadState.Initial)
                {
                    reader.MoveToContent();
                }
                // try either atom or rss reading
                if (atom.CanRead(reader))
                {
                    GenericFeedFormatter = atom;
                }
                if (rss.CanRead(reader))
                {
                    GenericFeedFormatter = rss;
                }
                if (GenericFeedFormatter == null)
                {
                    return null;
                }
                GenericFeedFormatter.ReadFrom(reader);
                feed = GenericFeedFormatter.Feed;
            }
        }
        return feed;
    }
}

现在您可以将对象数据源指向上述类,然后像这样评估 ListView 或 RadGrid 中的一些内容:

<%# Eval("Title.Text") %>

用几个 feedburner 饲料进行测试,效果很好。

于 2010-10-08T01:17:24.390 回答
1

我稍微改进了 JamesR 的代码,它现在返回一个成功布尔值并接受一个 ByRef 联合供稿对象;

public static class FeedParser
{
    public static bool Parse(string url, ref SyndicationFeed feed)
    {
        XmlReaderSettings settings = new XmlReaderSettings();
        settings.IgnoreWhitespace = true;
        settings.CheckCharacters = true;
        settings.CloseInput = true;
        settings.IgnoreComments = true;
        settings.IgnoreProcessingInstructions = true;
        settings.DtdProcessing = DtdProcessing.Prohibit;

        if (string.IsNullOrEmpty(url)) return false;

        using (XmlReader reader = XmlReader.Create(url, settings))
        {
            SyndicationFeedFormatter formatter = null;
            Atom10FeedFormatter atom_formatter = new Atom10FeedFormatter();
            Rss20FeedFormatter rss_formatter = new Rss20FeedFormatter();

            if (reader.ReadState == ReadState.Initial) reader.MoveToContent();

            if (atom_formatter.CanRead(reader)) formatter = atom_formatter;
            if (rss_formatter.CanRead(reader)) formatter = rss_formatter;
            if (formatter == null) return false;

            formatter.ReadFrom(reader);
            feed = formatter.Feed;

            return true;
        }
    }        
}

可以像这样使用;

    SyndicationFeed feed=null;

    if(FeedParser.Parse(url,ref feed))
    {

    }
于 2010-12-15T15:06:20.400 回答
0

http://feeds.feedburner.com/punchfire?format=xml似乎是Atom提要,而不是RSS。rss.net 知道如何处理吗?

于 2010-02-04T11:07:32.177 回答