1

我一直在寻找这个问题的答案，但没有其他答案对我有用。我在 android 中使用序列化并序列化一个对象。问题是当我反序列化它时，我得到 EOFException 并且对象不会加载。我的保存代码：

FileOutputStream fileOut = null;
try {
    fileOut = context.openFileOutput("state.ser", Context.MODE_PRIVATE);
    ObjectOutputStream out = new ObjectOutputStream(fileOut);
    out.writeObject(MyObject);
    out.close();
    fileOut.close();
} catch (IOException i) {
    i.printStackTrace();
}

我的加载类抛出该异常：

FileInputStream fis;
try {
    fis = context.openFileInput("state.ser");
    ObjectInputStream is = new ObjectInputStream(fis);
    myObject = (MyObject) is.readObject(); //exception thrown from here
    is.close();
} catch (FileNotFoundException e) {
    generateMyObject();
} catch (Exception e) {
    e.printStackTrace();
}

我的对象的定义：

public class MyObject implements Serializable {
    private static final long serialVersionUID = 155986L;   
    public MyInnerObject[][] mio = null;
    public Boolean[] unassigned = null; 
}
public class MyInnerObject implements Serializable {
    private static final long serialVersionUID = 1L;    
    public boolean[] legals;
    public int ID;
    public int pos;
}

我究竟做错了什么？感谢您的所有回答。

编辑：堆栈跟踪

java.io.EOFException
java.io.DataInputStream.readBoolean(DataInputStream.java:69)
java.io.ObjectInputStream.readNewArray(ObjectInputStream.java:1462)
java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:760)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1981)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1938)
java.io.ObjectInputStream.readFieldValues(ObjectInputStream.java:1115)
java.io.ObjectInputStream.defaultReadObject(ObjectInputStream.java:455)
java.io.ObjectInputStream.readObjectForClass(ObjectInputStream.java:1347)
java.io.ObjectInputStream.readHierarchy(ObjectInputStream.java:1244)
java.io.ObjectInputStream.readNewObject(ObjectInputStream.java:1833)
java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:762)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1981)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1938)
java.io.ObjectInputStream.readNewArray(ObjectInputStream.java:1490)
java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:760)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1981)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1938)
java.io.ObjectInputStream.readNewArray(ObjectInputStream.java:1490)
java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:760)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1981)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1938)
java.io.ObjectInputStream.readFieldValues(ObjectInputStream.java:1115)
java.io.ObjectInputStream.defaultReadObject(ObjectInputStream.java:455)
java.io.ObjectInputStream.readObjectForClass(ObjectInputStream.java:1347)
java.io.ObjectInputStream.readHierarchy(ObjectInputStream.java:1244)
java.io.ObjectInputStream.readNewObject(ObjectInputStream.java:1833)
java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:762)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1981)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:1938)
com.example.myApp.Cell.loadState(Cell.java:224)
... rest is only where in app it appeared

即使这只是警告，对象也不会加载，所以我不能使用它。

4

2 回答 2

1

我不知道这是否对您有帮助，但这里它说 Android 中的序列化可能会因大量整数数组而出现问题。在您的情况下，您有一个布尔数组，无论如何它都是一个整数。

我会尝试通过剥离一些可序列化数据（例如，仅序列化部分信息）来进行测试，以查看问题是否与数组有关。

此外，这可能很明显，但可能不是...确保您没有加载已使用不同版本的对象保存的文件（例如，您保存对象进行一些测试，然后将变量添加到您的类，现在您正在尝试反序列化）。

于 2014-02-20T20:42:21.960 回答
0

该文件为空或短。创建它时您必须遇到异常。

于 2014-02-20T20:27:12.070 回答