php - PHP SQLSRV OUTPUT PARAMETER 未能返回

Question

存储过程

USE [testtbl]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [dbo].[sptest]

@LeadID Bigint out
AS
insert into Lead (Name) values('test');
select @LeadID =@@IDENTITY;

//存储过程

<?php

$arraysql(array($_POST[],SQLSRV_PARAM_OUT));

  $objFilter=new Filter();
  $spCall="{call dbo.sptest(?)}";
  $objFilter->InsertQuery($spCall,$arraysql);
?>

<?php
function InsertQuery($spCall,$parameter){
        $serverName = ".";
        $connectionInfo = array("Database"=>"php","UID"=>"","PWD"=>"");
        $conn = sqlsrv_connect( $serverName, $connectionInfo);

        if(!$conn){

            echo "Connection could not be established.\n";
            die( print_r( sqlsrv_errors(), true));
            sqlsrv_close($conn);
        }
        $resource=sqlsrv_prepare($conn, $spCall, $parameter);

        sqlsrv_next_result($resource);
        sqlsrv_fetch($resource);


         //resqlsrv_get_field($resource,0);
       // sqlsrv_close($conn);
     }
?>

我没有粘贴所有内容，因为它太长了，那么如何从 LeadID 获取返回值？无论如何，我需要声明数组以将其发送到插入查询吗？我试过了，但我仍然没有得到 LeadID