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如果我有这个长字符串：

WAITLIST, 91630, ACCY 2001 , 10, Intro Financial Accounting, 3.00, Zou, Y, DUQUES 251,     TR09:35AM   - 10:50AM, 01/13/14   - 04/28/14 , , WAITLIST, 90003, ACCY 2001 , 11, Intro Financial Accounting, 3.00, Zou, Y, DUQUES 254, TR11:10AM - 12:25PM, 01/13/14 - 04/28/14 , , OPEN, 91212, ACCY 2001 , 12, Intro Financial Accounting, 3.00, Zou, Y, 1957 E B12, TR02:20PM - 03:35PM, 01/13/14 - 04/28/14 , , WAITLIST, 90004, ACCY 2002 , 10, Intro Managerial Accounting, 3.00, Linsley, C, FNGR 222, TR11:10AM - 12:25PM, 01/13/14 - 04/28/14 , ,

我想搜索“，”并在每次出现后直接添加一个换行符，所以我的长字符串如下所示：

WAITLIST 91630 ACCY 2001 10 Intro Financial Accounting 3.00 Zou, Y DUQUES 251 TR09:35AM - 10:50AM 01/13/14 - 04/28/14
WAITLIST 90003 ACCY 2001 11 Intro Financial Accounting 3.00 Zou, Y DUQUES 254 TR11:10AM - 12:25PM 01/13/14 - 04/28/14 
OPEN 91212 ACCY 2001 12 Intro Financial Accounting 3.00 Zou, Y 1957 E B12 TR02:20PM - 03:35PM 01/13/14 - 04/28/14 

ETC....

我在想我可以使用 stripos 记录每个“，”的位置并将其添加到数组中。然后我可以使用 for 循环遍历数组并在每个双逗号的位置后附加一个 '<br>'。那行得通吗？干杯!

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2 回答 2

2

只需用<br>using替换字符串str_replace：

$result = str_replace(", ,", "<br>", $str);
于 2014-02-19T07:48:10.937 回答
1

尝试str_replace：

$str = 'WAITLIST, 91630, ACCY 2001 , 10, Intro Financial Accounting, 3.00, Zou, Y, DUQUES 251,     TR09:35AM   - 10:50AM, 01/13/14   - 04/28/14 , , WAITLIST, 90003, ACCY 2001 , 11, Intro Financial Accounting, 3.00, Zou, Y, DUQUES 254, TR11:10AM - 12:25PM, 01/13/14 - 04/28/14 , , OPEN, 91212, ACCY 2001 , 12, Intro Financial Accounting, 3.00, Zou, Y, 1957 E B12, TR02:20PM - 03:35PM, 01/13/14 - 04/28/14 , , WAITLIST, 90004, ACCY 2002 , 10, Intro Managerial Accounting, 3.00, Linsley, C, FNGR 222, TR11:10AM - 12:25PM, 01/13/14 - 04/28/14 , ,';
$val = str_replace(', ,', '<br />', $str);
echo $val;
于 2014-02-19T07:47:55.823 回答