19

我想要的是有一个选项菜单,用户可以在其中选择在以下菜单之间导航:

  1. 触摸一个按钮,然后按下轨迹球将其选中
  2. 从 Gestures Builder 绘制预定义的手势

就目前而言,我已经创建了我的按钮OnClickListener和手势GestureOverlayView。然后我Activity根据使用按下按钮还是执行手势来选择开始新的。但是,当我尝试绘制手势时,它没有被拾取。只有按下按钮才会被识别。以下是我的代码:

public class Menu extends Activity implements OnClickListener, OnGesturePerformedListener {


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    //create TextToSpeech
    myTTS = new TextToSpeech(this, this);
    myTTS.setLanguage(Locale.US);

    //create Gestures
    mLibrary = GestureLibraries.fromRawResource(this, R.raw.gestures);
    if (!mLibrary.load()) {
     finish();
    }

    // Set up click listeners for all the buttons.
    View playButton = findViewById(R.id.play_button);
    playButton.setOnClickListener(this);
    View instructionsButton = findViewById(R.id.instructions_button);
    instructionsButton.setOnClickListener(this);
    View modeButton = findViewById(R.id.mode_button);
    modeButton.setOnClickListener(this);
    View statsButton = findViewById(R.id.stats_button);
    statsButton.setOnClickListener(this);
    View exitButton = findViewById(R.id.exit_button);
    exitButton.setOnClickListener(this);

    GestureOverlayView gestures = (GestureOverlayView) findViewById(R.id.gestures);
    gestures.addOnGesturePerformedListener(this);
}

public void onGesturePerformed(GestureOverlayView overlay, Gesture gesture) {
  ArrayList<Prediction> predictions = mLibrary.recognize(gesture);

 // We want at least one prediction
 if (predictions.size() > 0) {
 Prediction prediction = predictions.get(0);
 // We want at least some confidence in the result
 if (prediction.score > 1.0) {
  // Show the gesture
   Toast.makeText(this, prediction.name, Toast.LENGTH_SHORT).show();
   //User drew symbol for PLAY
    if (prediction.name.equals("Play")) {
       myTTS.shutdown();
       //connect to game
      // User drew symbol for INSTRUCTIONS
     } else if (prediction.name.equals("Instructions")) {
           myTTS.shutdown();
           startActivity(new Intent(this, Instructions.class));
       // User drew symbol for MODE
   } else if (prediction.name.equals("Mode")){
      myTTS.shutdown();
      startActivity(new Intent(this, Mode.class));
       // User drew symbol to QUIT
  } else {
      finish();
   }
  }
 }
}

@Override
    public void onClick(View v) {
      switch (v.getId()){
      case R.id.instructions_button:
         startActivity(new Intent(this, Instructions.class));
         break;
      case R.id.mode_button:
         startActivity(new Intent(this, Mode.class));
         break;
      case R.id.exit_button:
         finish();
         break;
  }  
}

任何建议将不胜感激!

4

1 回答 1

2

如果我理解正确,您想在同一个视图上执行点击动作和手势动作,我不知道如何实现这一点,但是,我们可以在按钮后面有不可见的视图来处理手势,顶部的按钮将处理点击活动照常。

默认计算器应用程序使用这种方法在普通模式和高级模式之间进行切换。

计算器来源

请参阅 com.android.calculator2.PanelSwitcher - 用于手势事件 com.android.calculator2.EventListener - 用于点击事件

希望能帮助到你。

于 2011-04-04T06:39:45.177 回答