-3

任何人都知道如何从这张表中获得最近的最高分：

----------------------------------------
|id |game_id |level |score |date       |
----------------------------------------
|1  |0       |1     |90    |1391989720 |
|1  |0       |1     |95    |1391989721 |
|1  |0       |1     |95    |1391989722 |
|1  |1       |1     |4     |1391989723 |
|1  |1       |1     |8     |1391989724 |
|1  |1       |2     |6     |1391989725 |
----------------------------------------

到目前为止，我有这个：

SELECT progress_max.game_id, 
       progress_max.level, 
       progress_max.date AS max_date,              
       max_score 
FROM 
(
    SELECT game_id, level, MAX(score) AS max_score
    FROM cdu_user_progress 
    WHERE lesson_id = 1 
    GROUP BY game_id, level 
) AS ms 
JOIN cdu_user_progress progress_max ON progress_max.game_id = ms.game_id AND progress_max.level = ms.level AND progress_max.score = ms.max_score 
WHERE progress_max.lesson_id = 1 
GROUP BY game_id, level

但这只会让我获得第一个最高分（日期 1391989721）......

4

1 回答 1

1

有一个更简单的解决方案可以order by用来获得最好的最新分数：

select game_id, level, score, date 
from cdu_user_progress
where id = 1
order by score desc, date desc
limit 1

要获得所有最好的分数和他们的最新时间，您需要加入。

select a.game_id, a.level, a.score, max(p.date) 
from (select game_id, level, max(score) as score
from cdu_user_progress
group by game_id, level) as a
inner join cdu_user_progress p
on a.game_id = p.game_id, a.level = p.level, a.score = p.score
group by a.game_id, a.level, a.score

实际上，由于您的问题不够清楚，我不确定这是否是您要找的。

于 2014-02-14T16:13:48.457 回答