9

测试元素是否存在的标准lxml.objectify方法是什么？

示例 XML：

<?xml version="1.0" encoding="utf-8"?>
<Test>
  <MyElement1>sdfsdfdsfd</MyElement1>
</Test>

代码

from lxml import etree, objectify
with open('config.xml') as f:
    xml = f.read()
root = objectify.fromstring(xml)

print root.MyElement1
print root.MyElement17  # AttributeError: no such child: MyElement17

那么，在特定路径上写东西的最简单解决方案是什么？

root.MyElement1.Blah = 'New'  # this works because MyElement1 already exists
root.MyElement17.Blah = 'New'  # this doesn't work because MyElement17 doesn't exist
root.MyElement1.Foo.Bar = 'Hello' # this doesn't as well... How to do this shortly ?
4

2 回答 2

7

findNone如果元素不存在，方法将返回。

>>> xml = '''<?xml version="1.0" encoding="utf-8"?>
... <Test>
...   <MyElement1>sdfsdfdsfd</MyElement1>
... </Test>'''
>>>
>>> from lxml import objectify
>>> root = objectify.fromstring(xml)
>>> root.find('.//MyElement1')
'sdfsdfdsfd'
>>> root.find('.//MyElement17')
>>> root.find('.//MyElement17') is None
True

根据问题编辑更新：

>>> from lxml import objectify
>>>
>>> def add_string(parent, attr, s):
...     if len(attr) == 1:
...         setattr(parent, attr[0], s)
...     else:
...         child = getattr(parent, attr[0], None)
...         if child is None:
...             child = objectify.SubElement(parent, attr[0])
...         add_string(child, attr[1:], s)
...
>>> root = objectify.fromstring(xml)
>>> add_string(root, ['MyElement1', 'Blah'], 'New')
>>> add_string(root, ['MyElement17', 'Blah'], 'New')
>>> add_string(root, ['MyElement1', 'Foo', 'Bar'], 'Hello')
>>>
>>> root.MyElement1.Blah
'New'
>>> root.MyElement17.Blah
'New'
>>> root.MyElement1.Foo.Bar
'Hello'
于 2014-02-14T10:15:21.900 回答
5

您可以使用getattr：

if getattr(root, 'MyElement17', None):
     # do something
于 2014-02-14T10:15:12.837 回答