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我正在寻找一种方法来模拟其他基于 sql 的 dbms 中可用的“汇总”。需要明确的是，我知道如何进行小计，这不是我所追求的。我也知道我可能可以通过编程方式做到这一点。但是，如果可以使用一个（或几个）sql 语句，我宁愿这样做。

例如，对于这样的表：product_type, order_amount, date 我会寻找一份报告，该报告显示按产品类型和日期分组的所有数据，其中一行显示产品类型和日期每次更改时 order_amount 的小计.

我被限制在 android 上使用 sqlite。我知道足够多的 sql 可能会伤害数据库，但显然不足以模拟汇总，此时我认为这是不可能的。

任何见解（即使“不，它不可能”）表示赞赏。

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3 回答 3

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这是一种在 sqlite 下模拟汇总的方法。我偶然发现了 2007 年在数据库论坛上询问小计和总计的答案。我将在这里用我的简化案例进行总结。

我有一个表股票，其中包含 Ticker_Symbol(Text)、Underlying(Text) 和 Quantity(Integer) 等字段。对于这个例子，这些就足够了。

Rollup 可以通过使用来自 sqlite 的以下调用来模拟：

select Ticker_Symbol,Underlying,Quantity from (
select '1' orderCol, Ticker_Symbol,Underlying,Quantity from stocks 
union  
select '2' orderCol, Ticker_Symbol, 'Subtotal' as Underlying, Sum(Quantity) as Quantity from stocks 
group by Ticker_Symbol 
union 
select '99' orderCol, '_' as Ticker_Symbol, 'GrandTotal' as Underlying, sum(Quantity) as Quantity from stocks) 
as t1  order by case  when orderCol=99 then 1 else 0 end, Ticker_Symbol, orderCol;

这会产生类似于以下的输出：

|Ticker_Symbol |底层证券|数量|
|--------|----------|--------|
AAPL AAPL 500
AAPL AAPL 1000
AAPL AAPL 2000
AAPL 小计 3500
AAPL140222P00500000 AAPL 10
AAPL140222P00500000 小计 10
IBM140322C00180000 IBM 25
IBM140322C00180000 小计 25
R140222C00067500 R 10
R140222C00067500 小计 10
VLCCF VLCCF 300
VLCCF VLCCF 2000
VLCCF 小计 2300
_ 总计 5845

不幸的是，我找不到避免使用 Ticker_Symbol 的方法。理想情况下，最好将当前的 Ticker_Symbol 替换为“Subtotal”（或 GrandTotal），但这不起作用。还要注意使用“_”来确保 GrandTotal 确实出现在最后一行。

我希望这对其他人有帮助，如果有人有办法让它变得更好，请补充。

于 2014-02-14T00:27:25.910 回答
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我自己也遇到了同样的问题-subtotals在 中进行模拟SQLite3，这就是我的发现：

with counter(numm)as(select 1 union all select numm+1 from counter where numm<34),
str(par,node)as(select 1, numm from counter where numm in(2,5,8,11)union 
select 11, numm from counter where numm in(12)union 
select 12, numm from counter where numm in(13,17,20)union 
select 13, numm from counter where numm in(14,15,16)union 
select 17, numm from counter where numm in(18,19)union 
select 2, numm from counter where numm in(3,4)union 
select 20, numm from counter where numm in(21)union 
select 21, numm from counter where numm in(22,23)union 
select 5, numm from counter where numm in(6,7)union 
select 8, numm from counter where numm in(9,10)union 
select null, numm from counter where numm in(1)),
struct(par,node,clevel)as(select par,node,0 from str where par is null union all select c.par,c.node,s.clevel+1 from str c join struct s on s.node=c.par)/*struct*/,
namez(namee,node)as(select 'Grandtotal', numm from counter where numm in(1)union
select 'Subtotal1', numm from counter where numm in(2)union
select 'Subtotal2', numm from counter where numm in(5)union
select 'Subtotal3', numm from counter where numm in(8)union
select 'Subtotal4', numm from counter where numm in(11)union
select 'Subtotal5', numm from counter where numm in(12)union
select 'Subtotal6', numm from counter where numm in(13)union
select 'Subtotal7', numm from counter where numm in(17)union
select 'Subtotal8', numm from counter where numm in(20)union
select 'Subtotal9', numm from counter where numm in(21)union
select 'value10', numm from counter where numm in(18)union
select 'value11', numm from counter where numm in(19)union
select 'value12', numm from counter where numm in(22)union
select 'value2', numm from counter where numm in(4)union
select 'value3', numm from counter where numm in(6)union
select 'value4', numm from counter where numm in(7)union
select 'value5', numm from counter where numm in(9)union
select 'value6', numm from counter where numm in(10)union
select 'value7', numm from counter where numm in(14)union
select 'value8', numm from counter where numm in(15)union
select 'value9', numm from counter where numm in(16)union
select 'valueN', numm from counter where numm in(23)union
select 'vaule1', numm from counter where numm in(3)),
some_random_values(node,val)as(
select node,
case node 
  when 3 then 10 when 4 then 33 when 6 then 123 when 7 then 2 
  when 9 then 321 when 10 then 202 when 14 then 2 when 15 then 88 
  when 16 then 56 when 18 then 17 when 19 then 345 when 22 then 99 when 23 then 9 
  else 0 
end from str),
sval(par,node,val)as(select s.par,s.node,a.val from str s join some_random_values a on a.node=s.node),
recur(par,node,val)as(
select * from sval where par in(select par from str group by par having(node)>1)
union all
select b.pAR,b.node,a.val+b.val
from recur a join sval b on b.node = a.par)
select s.par,s.node,substr('                            ',1,s.clevel*5)||n.namee name,v.val
from struct s join namez n on n.node=s.node
join(select par,node,sum(val)val from recur group by 1,2)v on v.node=s.node
order by s.node

示例可能看起来有点复杂。主要部分以recur(par,node,val).

上运行良好SQLite 3.9.1。

于 2018-08-13T13:52:17.807 回答
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我参考了 TrustNoOne's Answer 的方法使用它。

    select securityname,bal,Total from (
select 1 orderCol,sectorname, '#' || COALESCE (sectorname,'') as securityname ,'' bal ,'' as Total from tablename 
group by sectorname  --Title
union 
select 2 orderCol,sectorname, securityname,bal,'' from tablename --Items
union  
select 3 orderCol,sectorname, sectorname || '- Subtotal :' as securityname ,'',Sum(bal) as Total from tablename 
group by sectorname --SubTotal
union 
select 99 orderCol,'_' sectorname, 'Grand Total :' as securityname ,'', sum(bal) as Total from tablename
group by 1,2,3 --GrandTotal
)
安全名称 数量 全部的
#组 1：
项目1 50.0
项目2 30.0
Group1-小计 80
#组2：
项目1 10.0
Group2-小计 10
累计 90
于 2021-07-22T03:47:17.280 回答