6

我希望有人可以帮助我解决间歇性连接问题，我正在使用 HttpsURLConnection 的代码。我正在使用的代码如下：

HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
            conn.setReadTimeout(10 * 1000); 
if conn.getResponseCode() != 200) { 
            Log.v(TAG, "error code:" + conn.getResponseCode()); 
}

每次我使用它来拉 json 文件时，连接都会第一次工作。但是，当我再次使用连接发送命令时，它总是第一次失败。如果我快速发送命令（在 5 秒内），它通常会起作用，但如果我等待一段时间，它就会失败。我不认为它是 SSL 问题，因为它第一次正确连接，但我在这里可能是错的。我还尝试了许多不同的变体，例如添加：

conn.setUseCaches(false); 
conn.setRequestProperty("Connection","Keep-Alive"); 
conn.getHostnameVerifier(); 
conn.getSSLSocketFactory(); 
conn.setDoOutput(true); 
conn.setDoInput(true); 
conn.setRequestMethod("POST"); 
conn.wait(100);

但是，我没有运气。任何帮助将不胜感激。

4

3 回答 3

9

System.setProperty("http.keepAlive", "false");做之前先试试

HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
于 2010-02-01T11:02:35.113 回答
2

试试这个代码 - 它对我来说非常可靠：

public static final String USER_AGENT = "Mozilla/5.0 (Linux; U; Android 1.1; en-us;dream) AppleWebKit/525.10+ (KHTML, like Gecko) Version/3.0.4 Mobile Safari/523.12.2";
private DefaultHttpClient getThreadSafeHttpClient() {
    final HttpParams params = new BasicHttpParams();
    params.setParameter("http.useragent", USER_AGENT);
    HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
    HttpProtocolParams.setContentCharset(params, "UTF-8");
    final SchemeRegistry registry = new SchemeRegistry();
    registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
    final SSLSocketFactory sslSocketFactory = SSLSocketFactory.getSocketFactory();
    sslSocketFactory.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);
    registry.register(new Scheme("https", sslSocketFactory, 443));
    final ThreadSafeClientConnManager manager = new ThreadSafeClientConnManager(params, registry);
    final DefaultHttpClient httpclient = new DefaultHttpClient(manager, params);
    // how to handle retries
    final HttpRequestRetryHandler myRetryHandler = new HttpRequestRetryHandler() {
        public boolean retryRequest(final IOException exception, final int executionCount, final HttpContext context) {
            if (executionCount >= 5) {
                // Do not retry if over max retry count
                return false;
            }
            if (exception instanceof NoHttpResponseException) {
                // Retry if the server dropped connection on us
                return true;
            }
            if (exception instanceof SSLHandshakeException) {
                // Do not retry on SSL handshake exception
                return false;
            }
            final HttpRequest request = (HttpRequest) context.getAttribute(ExecutionContext.HTTP_REQUEST);
            final boolean idempotent = !(request instanceof HttpEntityEnclosingRequest);
            if (idempotent) {
                // Retry if the request is considered idempotent
                return true;
            }
            return false;
        }

    };
    httpclient.setHttpRequestRetryHandler(myRetryHandler);
    return httpclient;
}
于 2010-01-31T23:29:58.193 回答
0

只是对上面 m6tt 的回答的一点补充：

private static void disableConnectionReuseIfNecessary() {
    // HTTP connection reuse which was buggy pre-froyo
    if (!Constants.SUPPORTS_FROYO) {
        System.setProperty("http.keepAlive", "false");
    }
}
于 2011-12-01T10:16:14.013 回答