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我想使用Boost.Range和C++1y lambda 和 init-capture计算两个向量的元素差异。减去一个向量的固定（即第一个）元素的更简单的情况是有效的。但是，当我尝试通过在第二个范围内增加迭代器（并使 lambda mutable）来计算“矢量化差异”时，会出现编译器错误。示例代码（请注意，我没有使用通用 lambda，因此 g++ 4.8 和 Clang SVN 都可以解析此代码）：

#include <iostream>
#include <iterator>
#include <vector>
#include <boost/range/algorithm.hpp>
#include <boost/range/adaptors.hpp>

template<class R>
auto delta_beg(R const& rng1, R const& rng2)
{
    using Elem = typename R::value_type;
    return rng1 | boost::adaptors::transformed(
        [first2 = begin(rng2)](Elem const& e) {
        return e - *first2;
    });
}

template<class R>
auto delta_rng(R const& rng1, R const& rng2)
{
    using Elem = typename R::value_type;
    return rng1 | boost::adaptors::transformed(
        [first2 = begin(rng2)](Elem const& e) mutable {
        return e - *first2++;
    });
}

int main()
{
    auto r1 = std::vector<int>{ 8, 10, 12, 15 };
    auto r2 = std::vector<int>{ 1,  2,  9, 13 };

    // prints 7, 9, 11, 14
    boost::copy(delta_beg(r1, r2), std::ostream_iterator<int>(std::cout, ",")); std::cout << "\n";

    // ERROR, should print 7, 8, 3, 2
    boost::copy(delta_rng(r1, r2), std::ostream_iterator<int>(std::cout, ",")); std::cout << "\n";
}

活生生的例子。这里 g++ 和 Clang 都抱怨

'boost::mpl::eval_if, boost::result_of]::__lambda1(const int&)>, boost::mpl::identity >::f_ {aka struct boost::result_of] 中没有名为 'type' 的类型： :__lambda1(const int&)>}' typedef typename f_::type type;

问题：发生了什么事？

4

1 回答 1

2

只是闭包类型没有boost::mpl显然需要的嵌套类型定义。如果将 lambda 表达式转换为std::function：

#include <iostream>
#include <iterator>
#include <vector>
#include <boost/range/algorithm.hpp>
#include <boost/range/adaptors.hpp>

template<class R>
auto delta_beg(R const& rng1, R const& rng2)
{
    using Elem = typename R::value_type;
    std::function<Elem(Elem const&)> f = 
        [first2 = begin(rng2)](Elem const& e) { return e - *first2; };
    return rng1 | boost::adaptors::transformed(f);
}

template<class R>
auto delta_rng(R const& rng1, R const& rng2)
{
    using Elem = typename R::value_type;
    std::function<Elem(Elem const&)> f = 
        [first2 = begin(rng2)](Elem const& e) mutable { return e - *first2++; };
    return rng1 | boost::adaptors::transformed(f);
}

int main()
{
    auto r1 = std::vector<int>{ 8, 10, 12, 15 };
    auto r2 = std::vector<int>{ 1,  2,  9, 13 };

    // prints 7, 9, 11, 14
    boost::copy(delta_beg(r1, r2), std::ostream_iterator<int>(std::cout, ",")); std::cout << "\n";

    // ERROR, should print 7, 8, 3, 2
    boost::copy(delta_rng(r1, r2), std::ostream_iterator<int>(std::cout, ",")); std::cout << "\n";
}

现场演示。

于 2014-02-12T10:18:02.713 回答