我想创建一个基于Hibernate-3和Spring Framework的 Java 应用程序。为了简化这个过程,我找到了能够对现有数据库执行逆向工程的hibernate3-maven-plugin 。
这里有一个POM的例子:
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>hibernate3-maven-plugin</artifactId>
<version>2.2</version>
<configuration>
<components>
<component>
<name>hbm2java</name>
<outputDirectory>src/main/java</outputDirectory>
<implementation>jdbcconfiguration</implementation>
</component>
<component>
<name>hbm2dao</name>
<outputDirectory>src/main/java</outputDirectory>
<implementation>jdbcconfiguration</implementation>
</component>
</components>
<componentProperties>
<revengfile>/src/main/resources/model.reveng.xml</revengfile>
<propertyfile>/src/main/resources/hibernate.properties</propertyfile>
<jdk5>true</jdk5>
<ejb3>true</ejb3>
</componentProperties>
</configuration>
<dependencies>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>5.1.18</version>
</dependency>
<dependency>
<groupId>cglib</groupId>
<artifactId>cglib-nodep</artifactId>
<version>2.1_3</version>
</dependency>
</dependencies>
<executions>
<execution>
<phase>compile</phase>
<goals>
<goal>hbm2java</goal>
<goal>hbm2dao</goal>
</goals>
</execution>
</executions>
</plugin>
然后我设置了 Spring 的上下文:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.0.xsd">
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="gomer" />
</bean>
<bean id="entityManager" factory-bean="entityManagerFactory" factory-method="createEntityManager"/>
<bean id="user" class="ru.tomtrix.first.db.UserHome">
<property name="entityManager" ref="entityManager"/>
</bean>
</beans>
它完美地生成了一个Entity文件和一个DAO文件,除了以下内容。在 DAO 文件中有一个 EntityManager:
@Stateless
public class UserHome {
private static final Log log = LogFactory.getLog(UserHome.class);
@PersistenceContext private EntityManager entityManager;
...而且这个领域还没有二传手!最终 Spring 抛出异常:
Invalid property 'entityManager' of bean class [ru.tomtrix.first.db.UserHome]: Bean property 'entityManager' is not writable or has an invalid setter method. Does the parameter type of the setter match the return type of the getter?
当然,手动编写 setter 并不是一个好习惯。我认为有一种方法可以正确地注入经理。那么如何在不重写生成文件的情况下做到这一点呢?
对应信息:
1)我想创建一个独立的应用程序(并可能在像Tomcat这样的应用程序服务器中运行它)
2)model.reveng.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-reverse-engineering SYSTEM "http://www.hibernate.org/dtd/hibernate-reverse-engineering-3.0.dtd">
<hibernate-reverse-engineering>
<table-filter match-name=".*" package="ru.tomtrix.first.db"/>
</hibernate-reverse-engineering>
3)持久性.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="gomer" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<class>User</class>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect"/>
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.connection.username" value="root"/>
<property name="hibernate.connection.password" value="1234"/>
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/users"/>
</properties>
</persistence-unit>
</persistence>