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我有一个句子列表，基本上我的目标是用正确的拼写“opposite,near,above,behind”等替换所有不同的介词“opp,nr,off,abv,behnd”。单词的 soundex 代码是相同的，所以我需要构建一个表达式来逐字迭代这个列表，如果 soundex 相同，则用正确的拼写替换它。

一个例子 - ['杰克站在树旁'，
'他们完全按照他的计划'，
'站在柜台前'，
'去加油站']

所以我需要用正确的完整形式替换单词 nr、abv、opp 和 twrds。forward 和 twrds 的 soundex 代码是一样的，所以应该替换它。
我需要遍历这个列表。
这是 soundex 算法： 

import string

allChar = string.uppercase + string.lowercase
charToSoundex = string.maketrans(allChar, "91239129922455912623919292" * 2)

def soundex(source):
    "convert string to Soundex equivalent"

    # Soundex requirements:
    # source string must be at least 1 character
    # and must consist entirely of letters
    if (not source) or (not source.isalpha()):
    return "0000"

    # Soundex algorithm:
    # 1. make first character uppercase
    # 2. translate all other characters to Soundex digits
    digits = source[0].upper() + source[1:].translate(charToSoundex)

    # 3. remove consecutive duplicates
    digits2 = digits[0]
    for d in digits[1:]:
        if digits2[-1] != d:
           digits2 += d

    # 4. remove all "9"s
    # 5. pad end with "0"s to 4 characters
    return (digits2.replace('9', '') + '000')[:4]

if __name__ == '__main__':
   import sys
   if sys.argv[1:]:
      print soundex(sys.argv[1])
   else:
    from timeit import Timer
    names = ('Woo', 'Pilgrim', 'Flingjingwaller')
    for name in names:
        statement = "soundex('%s')" % name
        t = Timer(statement, "from __main__ import soundex")
        print name.ljust(15), soundex(name), min(t.repeat())

我是新手，所以如果您有其他方法可以建议，将不胜感激..谢谢。

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1 回答 1

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我将使用附魔模块：

import enchant
d = enchant.Dict("en_US")

phrase = ['Jack was standing nr the tree' ,
'they were abv everything he planned' ,
'Just stand opp the counter' ,
'Go twrds the gas station']

output = []
for section in phrase:
    sect = ''
    for word in section.split():
        if d.check(word):
            sect += word + ' '
        else:
            for correct_word in d.suggest(word):
                if soundex(correct_word) == soundex(word):
                    sect +=  correct_word + ' '
    output.append(sect[:-1])
于 2014-10-03T09:16:42.583 回答