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我正在尝试将logfile（保存为文件的文本文件*.log）解析为 Visual Basic 2013 Express' DataGridView。日志文件使用空格作为分隔符，但日志的消息部分中有空格。这是日志文件的布局：

日期时间 ID Connection Type_of_message(command/response/status/etc) 消息（可能包含多个空格（每条消息的空格数量不同））

每个日志条目都是文件中的单独一行。

编辑：这是日志文件的示例：

2014-02-03 15:35:29 9900 3 Status: Listing directory [[server folder]]
2014-02-03 15:35:46 9900 3 Status: Invalid character sequence received, disabling UTF-8. Select UTF-8 option in site manager to force UTF-8.
2014-02-03 15:35:46 9900 3 Status: Calculating timezone offset of server...
2014-02-03 15:35:46 9900 3 Command: mtime "[[file name]]"
2014-02-03 15:35:46 9900 3 Response: 1382557913
2014-02-03 15:35:46 9900 3 Status: Timezone offsets: Server: -14400 seconds. Local: -18000 seconds. Difference: -3600 seconds.
2014-02-03 15:36:18 9900 2 Status: Connected to [[server name]]
2014-02-03 15:36:18 9900 1 Status: Starting upload of [[local folder name/file name (includes 3 spaces)]]
2014-02-03 15:36:18 9900 1 Command: cd "[[server folder]]"
2014-02-03 15:36:18 9900 2 Status: Starting upload of [[local folder name/file name (includes 3 spaces)]]
2014-02-03 15:36:18 9900 1 Response: New directory is: "[[server folder]]"
2014-02-03 15:36:18 9900 1 Command: put "[[local folder name/file name (includes 2 spaces)]]"
2014-02-03 15:36:18 9900 2 Command: cd "[[server folder]]"
2014-02-03 15:36:18 9900 1 Status: local: [[local folder name/file name (includes 3 spaces)]]=> remote:[[server folder]]
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1 回答 1

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它可能不漂亮，但它有效：

Dim line As String = "2014-02-03 15:35:29 9900 3 Status: Listing directory [[server folder]]"
Dim split As String() = line.Split(" "c)
Dim message As String = String.Join(" "c, split.Skip(5).ToArray)

这是假设您总共有 6 列，最后一列是您的消息。

编辑：正如@Andrew Morton 所建议的，可以重写拆分（无 LINQ）：

Dim split As String() = line.Split({" "c}, 6, StringSplitOptions.None)
于 2014-02-05T16:31:50.960 回答