我想在 Apache ODE 的源代码中使用 OpenJPA 创建一个新表。我创建了一个接口并提供了一个实现。我使用 Maven 编译了该过程并将其部署在 Apache Tomcat 上。但是,当我在 Apache ODE 引擎上运行 BPEL 流程时,出现错误:
org.apache.openjpa.persistence.PersistenceException:表/视图“ODE_POLICY_ATTACHMENT”不存在。
我在 ApacheODE\dao-jpa\src\main\resources\META-INF\persistence.xml 中添加了我的 PolicyAttachmentDAOImpl 类
persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
version="1.0">
<persistence-unit name="ode-dao">
<!--
This properties file is used specifically by the
OpenJPA Enhancer.
-->
<provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
<class>org.apache.ode.dao.jpa.ProcessDAOImpl</class>
<class>org.apache.ode.dao.jpa.PolicyAttachmentDAOImpl</class>
.............................................................
</persistence-unit>
我的 DAO(数据访问对象)接口:
public interface PolicyAttachmentDAO {
/**
* Get the process.
*
* @return process reference.
*/
ProcessDAO getProcess();
...............
}
然后我在这样的类中实现了它:
@Entity
@Table(name = "ODE_POLICY_ATTACHMENT")
/**
*
* OpenJPA implementation of the {@link PolicyAttachmentDAO} interface.
*
*/
public class PolicyAttachmentDAOImpl extends OpenJPADAO implements PolicyAttachmentDAO{
@Id
@Column(name = "POLICYATTACHMENT_ID")
@GeneratedValue(strategy = GenerationType.AUTO)
private Long _attachmentId;
@ManyToOne(fetch = FetchType.LAZY, cascade = { CascadeType.PERSIST })
@Column(name = "PROCESS_ID")
private ProcessDAOImpl _process;
@Basic
@Column(name = "POLICYATTACHMENT_NAME")
private String _attachmentName;
@Basic
@Column(name = "POLICYATTACHMENT_FILE_DATE")
private Date _attachmentFileDate;
public PolicyAttachmentDAOImpl(ProcessDAOImpl process, String policyAttachmentName, Date attachmentFileDate) {
_process = process;
_attachmentName = policyAttachmentName;
_attachmentFileDate = attachmentFileDate;
}
public ProcessDAO getProcess() {
return _process;
}
.....................
}
谁能指导我如何创建表格?
谢谢!彼得