I'm parsing HTML with BeautifulSoup. At the end, I would like to obtain the body contents, but without the body tags. But BeautifulSoup adds html, head, and body tags. I this googlegrops discussion one possible solution is proposed:
>>> from bs4 import BeautifulSoup as Soup
>>> soup = Soup('<p>Some paragraph</p>')
>>> soup.body.hidden = True
>>> soup.body.prettify()
u' <p>\n Some paragraph\n </p>'
This solution is a hack. There should be a better and obvious way to do it.
你的意思是让身体标签之间的一切？
在这种情况下，您可以使用：
import urllib2
from bs4 import BeautifulSoup
page = urllib2.urlopen('some_site').read()
soup = BeautifulSoup(page)
body = soup.find('body')
the_contents_of_body_without_body_tags = body.findChildren(recursive=False)
我发现获取正文内容的最简单方法是unwrap()从正文标签内部获取您的内容。
>>> html = "<p>Hello World</p>"
>>> soup = BeautifulSoup(html, "html5lib")
>>> print(soup)
<html><head></head><body><p>Hello World</p></body></html>
>>>
>>> soup.html.unwrap()
<html></html>
>>>
>>> print(soup)
<head></head><body><p>Hello World</p></body>
>>>
>>> soup.head.unwrap()
<head></head>
>>>
>>> print(soup)
<body><p>Hello World</p></body>
>>>
>>> soup.body.unwrap()
<body></body>
>>>
>>> print(soup)
<p>Hello World</p>
为了提高效率和可重用性，您可以将那些不需要的元素放在一个列表中并循环它们......
>>> def get_body_contents(html):
... soup = BeautifulSoup(html, "html5lib")
... for attr in ['head','html','body']:
... if hasattr(soup, attr):
... getattr(soup, attr).unwrap()
... return soup
>>>
>>> html = "<p>Hello World</p>"
>>> print(get_body_contents(html))
<p>Hello World</p>