自定义错误丢失自定义属性
哪些步骤将重现该问题:
创建函数
CREATE OR REPLACE FUNCTION public.utils ()
RETURNS void AS
$body$
this.dbError = function(message){
this.message = (message || '');
};
dbError.prototype = Error.prototype;
$body$
LANGUAGE 'plv8'
VOLATILE
RETURNS NULL ON NULL INPUT
SECURITY DEFINER
COST 100;
创建触发函数
CREATE OR REPLACE FUNCTION public.test_trigger func ()
RETURNS trigger AS
$body$
var fn = plv8.find_function('public.utils');
fn();
var err = new dbError('this is a dbError');
err.someProp = 'lalala';
throw err;
return NEW;
$body$
LANGUAGE 'plv8'
VOLATILE
CALLED ON NULL INPUT
SECURITY DEFINER
COST 100;
在任何表上设置此触发器而不是事件并尝试执行它
DO $$
plv8.find_function('public.utils')();
try{
plv8.execute('insert into Temp (field) value ($1)', [100]);
} catch(ex){
plv8.elog(NOTICE, ex instanceof dbError);
plv8.elog(NOTICE, ex.message);
plv8.elog(NOTICE, ex.someProp);
}
$$ LANGUAGE plv8;
我们会看到
true
this is a dbError
undefined
什么是预期的输出?
true
this is a dbError
lalala
如果我在一个范围内这样做 - 我会得到正确的结果
DO $$
this.dbError = function(message){
this.message = (message || '');
};
dbError.prototype = Error.prototype;
try{
var err = new dbError('this is a dbError');
err.someProp = 'lalala';
throw err;
} catch(ex){
plv8.elog(NOTICE, ex instanceof dbError);
plv8.elog(NOTICE, ex.message);
plv8.elog(NOTICE, ex.someProp);
}
$$ LANGUAGE plv8;
结果:
true
this is a dbError
lalala